将多层级xml解析为Map

/**
* 解析xml的工具类
* 1、将多层级xml解析为Map
*/
public class ParseXmlUtil {
public static final String TAG = "ParseXmlUtil"; /**
* 将xml格式响应报文解析为Map格式
*
* @param responseXmlTemp
* @return
* @throws DocumentException
*/
public static Map<String, Object> xml2map(String responseXmlTemp) throws DocumentException {
Document doc = DocumentHelper.parseText(responseXmlTemp);
Element rootElement = doc.getRootElement();
Map<String, Object> mapXml = new HashMap<>();
element2Map(mapXml, rootElement);
return mapXml;
} /**
* 使用递归调用将多层级xml转为map
*
* @param map
* @param rootElement
*/
private static void element2Map(Map<String, Object> map, Element rootElement) {
// 获得当前节点的子节点
List<Element> childElements = rootElement.elements();
Log.d(TAG, "element name :" + rootElement.getName() + " -- childElements size:" + childElements.size());
if (childElements.size() > 0) {
Map<String, Object> tempMap = new HashMap<>();
for (Element e : childElements) {
element2Map(tempMap, e);
map.put(rootElement.getName(), tempMap);
}
} else {
Log.d(TAG, "当前无子节点 name :" + rootElement.getName() + ":" + rootElement.getText());
map.put(rootElement.getName(), rootElement.getText());
}
}
}
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