Oracle拆分字符串,字符串分割的函数。
第一种:oracle字符串分割和提取
分割
create or replace function Get_StrArrayLength ( av_str varchar2, --要分割的字符串 av_split varchar2 --分隔符号 ) return number is lv_str varchar2(1000); lv_length number; begin lv_str:=ltrim(rtrim(av_str)); lv_length:=0; while instr(lv_str,av_split)<>0 loop lv_length:=lv_length+1; lv_str:=substr(lv_str,instr(lv_str,av_split)+length(av_split),length(lv_str)); end loop; lv_length:=lv_length+1; return lv_length; end Get_StrArrayLength;
提取
create or replace function Get_StrArrayStrOfIndex ( av_str varchar2, --要分割的字符串 av_split varchar2, --分隔符号 av_index number --取第几个元素 ) return varchar2 is lv_str varchar2(1024); lv_strOfIndex varchar2(1024); lv_length number; begin lv_str:=ltrim(rtrim(av_str)); lv_str:=concat(lv_str,av_split); lv_length:=av_index; if lv_length=0 then lv_strOfIndex:=substr(lv_str,1,instr(lv_str,av_split)-length(av_split)); else lv_length:=av_index+1; lv_strOfIndex:=substr(lv_str,instr(lv_str,av_split,1,av_index)+length(av_split),instr(lv_str,av_split,1,lv_length)-instr(lv_str,av_split,1,av_index)-length(av_split)); end if; return lv_strOfIndex; end Get_StrArrayStrOfIndex;
测试: select Get_StrArrayStrOfIndex('songguojun$@111111537','$',0) from dual
结果:
第二种:
本函数可以将“目标字符串”以“指定字符串”进行拆分,并通过表结构返回结果。代码如下:
CREATE OR REPLACE TYPE str_split IS TABLE OF VARCHAR2 (4000); CREATE OR REPLACE FUNCTION splitstr(p_string IN VARCHAR2, p_delimiter IN VARCHAR2) RETURN str_split PIPELINED AS v_length NUMBER := LENGTH(p_string); v_start NUMBER := 1; v_index NUMBER; BEGIN WHILE(v_start <= v_length) LOOP v_index := INSTR(p_string, p_delimiter, v_start); IF v_index = 0 THEN PIPE ROW(SUBSTR(p_string, v_start)); v_start := v_length + 1; ELSE PIPE ROW(SUBSTR(p_string, v_start, v_index - v_start)); v_start := v_index + 1; END IF; END LOOP; RETURN; END splitstr;
创建完毕后,我们来测试一下,例如执行如下SQL:
select * from table(splitstr('Hello,Cnblogs!',','));
其输出结果为一个两行的表,如下图:
将行转为列显示:
select a.column_value v1,b.column_value v2 from (select * from (select rownum rn,t.* from table(splitstr('Hello,Cnblogs!',',')) t)) a, (select * from (select rownum rn,t.* from table(splitstr('Hello,Cnblogs!',',')) t)) b where a.rn=1 and b.rn=2
如图:
转载于:https://www.cnblogs.com/zhichao-116/p/3645600.html