对于含多字节的字符串，进行截断的时候，要判断截断处是几字节字符，不能将多字节从中分割，避免截断后乱码
下面给出utf8和gb18030上的实现， 用任何一种都可以，可以先进行转码，用encode, decode;
方法1：对utf8: 参考：http://blog.csdn.net/marising/article/details/3452971
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def
subString(string,length):
if
length >=
len(string):
return
string
result =
‘‘
i =
0
p =
0
while
True:
ch =
ord(string[i])
#1111110x
if
ch >=
252:
p =
p +
6
#111110xx
elif
ch >=
248:
p =
p +
5
#11110xxx
elif
ch >=
240:
p =
p +
4
#1110xxxx
elif
ch >=
224:
p =
p +
3
#110xxxxx
elif
ch >=
192:
p =
p +
2
else:
p =
p +
1 if
p >=
length:
break;
else:
i =
p
return
string[0:i]
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方法2：对gb18030编码
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def
cut_string_off(string,s_len):
if
len(string)==0
or
s_len <=0:
return
string
elif
len(string)==1
or
s_len >=
len(string):
return
string
elif
s_len < len(string):
len_num=0
while
len_num < s_len:
tmp_c=ord(string[len_num])
if
tmp_c >0
and
tmp_c <=0x7F:
len_num+=1
continue
tmp_nextc=ord(string[len_num+1])
if
tmp_c >=
0x81
and
tmp_c <=0xFE
and
tmp_nextc>=0x40
and
tmp_nextc<=0xFE:
len_num+=2
continue
else:
len_num +=1;
continue
break
tmp =
string[0:len_num]
# print utf2gbk(tmp) return
tmp
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