我将使用C#中的OleDbDataAdapter在Access数据库中插入数据,但我在INSERT INTO命令中出现错误消息语法错误

BackgroundWorker worker = new BackgroundWorker();
OleDbDataAdapter dbAdapter new OleDbDataAdapter();
OleDbConnection dbConnection = new OleDbConnection("Provider=Microsoft.Jet.OLEDB.4.0;Data Source=E:\\PMS.mdb");
worker = new BackgroundWorker();
worker.WorkerReportsProgress = true;
worker.DoWork += InsertJob;
worker.ProgressChanged += InsertJobCompleted;
worker.RunWorkerAsync(args);

而InsertJob函数是：

private void InsertJob(object sender, DoWorkEventArgs e)
{
     var args = (InsertJobArgs)e.Argument;
     try
        {
            dbAdapter.SelectCommand = new OleDbCommand("SELECT * FROM Sheet", dbConnection);                
            dbAdapter.Fill(args.DataTable);
            var builder = new OleDbCommandBuilder(dbAdapter);
            var row = args.DataTable.NewRow();

            row["UserName"] = args.Entry.UserName;
            row["Password"] = args.Entry.Password;
            args.DataTable.Rows.Add(row);

            dbAdapter.InsertCommand = builder.GetInsertCommand();               
            dbAdapter.Update(args.DataTable);
            builder.Dispose();
        }
        catch (Exception ex)
        {
            args.Exception = ex;
            worker.ReportProgress(0, args);
            return;
        }
        worker.ReportProgress(100, args);
}

我在线收到错误：dbAdapter.Update(args.DataTable);

我尝试使用visual studio调试它,发现所有InsertCommand参数值都为null

我尝试在调用dbAdapter.Update(args.DataTable)之前通过此代码手动插入它;

dbAdapter.InsertCommand.Parameters[0].Value = args.Entry.UserName;
dbAdapter.InsertCommand.Parameters[1].Value = args.Entry.Password;

解决方法:

试试这个：

紧接着就行了

var builder = new OleDbCommandBuilder(dbAdapter);

添加两行

builder.QuotePrefix = "[";
builder.QuoteSuffix = "]";

这将告诉OleDbCommandBuilder将表和列名称包装在方括号中,生成一个INSERT命令

INSERT INTO [TableName] ...

而不是默认表格

INSERT INTO TableName ...

如果任何表或列名称包含空格或“有趣”字符,或者它们恰好是Access SQL中的保留字,则必须使用方括号. (在您的情况下,我怀疑您的表有一个名为[Password]的列,而PASSWORD是Access SQL中的保留字.)