Mysql 根据时间统计总数

代码写法:

    SELECT
date_format(examinee_pay_time, '%Y-%m-%d') as payDate,
COUNT(examinee_id) As realityApplyCount, <!-- 日缴费次数 -->
sum((CASE WHEN examinee_exam_score IS NULL THEN exam_fee ELSE END )) as realityApplyFee, <!-- 日缴费金额 -->
exam_id,
exam_name,
examinee_pay_status,
examinee_exam_status
FROM
schoolexam
INNER JOIN examinee e ON exam_id = exam_item_id AND exam_type = examinee_apply_type
AND (examinee_exam_status != '' OR ISNULL(examinee_exam_status))
AND examinee_pay_status = ""
<where>
=
</where>
GROUP BY
date_format(examinee_pay_time, '%Y-%m-%d')

结果如下:

Mysql 根据时间统计总数

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