LeetCode & Q88-Merge Sorted Array-Easy

Array Two Pointers

Description:

Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.

Note:

You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.

我现在意识到我的智商非常低...刚开始一直纠结于从前往后排,想的头都要炸了...看了眼discuss,感叹人类的智慧啊(主要还是题主太蠢)从后往前排的话,工作量小太多太多了!!

Solution:

public class Solution {
public void merge(int[] nums1, int m, int[] nums2, int n) {
int i = m -1;
int j = n -1;
int k = m + n - 1;
while (i >= 0 && j >= 0) {
if (nums1[i] > nums2[j]) {
nums1[k--] = nums1[i--];
} else {
nums1[k--] = nums2[j--];
}
}
while (j >= 0) {
nums1[k--] = nums2[j--];
}
while (i >= 0) {
nums1[k--] = nums1[i--];
}
}
}
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