以下Json结构是Neo4J apoc查询的结果.我想将此嵌套的Json转换为平坦的Json结构,如第二个json所示.
[
{
"child1": [
{
"_type": "EntityChild1",
"name": "Test222",
"_id": 2
}
],
"child2": [
{
"_type": "EntityChild2",
"name": "Test333",
"_id": 3,
"child2_child1": [
{
"_type": "EntityChild2_1",
"name": "Test444",
"_id": 6,
"child2_child1_child1": [
{
"_type": "EntityChild2_1_1",
"name": "Test555",
"_id": 7
}
]
}
]
}
],
"_type": "EntityParent",
"name": "Test000",
"_id": 1,
"child3": [
{
"_type": "EntityChild3",
"name": "Test111",
"_id": 4
}
],
"child4": [
{
"_type": "EntityChild4",
"name": "Test666",
"_id": 5
}
]
}
]
这是我要寻找的结果,我也希望将parentId附加到每个节点.如果特定节点没有父节点,则其父节点名称应为-1.
[
{
"_type": "EntityParent",
"name": "Test000",
"_id": 1,
"parentid": -1
},
{
"_type": "EntityChild1",
"name": "Test222",
"_id": 2,
"parentid": 1
},
{
"_type": "EntityChild2",
"name": "Test333",
"_id": 3,
"parentid": 1
},
{
"_type": "EntityChild2_1",
"name": "Test444",
"_id": 6,
"parentid": 3
},
{
"_type": "EntityChild2_1_1",
"name": "Test555",
"_id": 7,
"parentid": 6
},
{
"_type": "EntityChild3",
"name": "Test111 ",
"_id": 4,
"parentid": 1
},
{
"_type": "EntityChild4",
"name": "Test666",
"_id": 5,
"parentid": 1
}
]
让我知道是否需要进一步的信息.
解决方法:
您可以通过使用一个函数来采取迭代和递归的方法,该函数需要一个数组和一个实际级别的父ID.
如果属性以child开头,它将使用实际的_id再次调用该函数,并将所有项目推送到结果集中.
function getFlat(array, parentid) {
return array.reduce((r, o) => {
var temp = {};
r.push(temp);
Object.entries(o).forEach(([k, v]) => {
if (k.startsWith('child')) {
r.push(...getFlat(v, o._id));
} else {
temp[k] = v;
}
});
temp.parentid = parentid;
return r;
}, []);
}
var data = [{ child1: [{ _type: "EntityChild1", name: "Test222", _id: 2 }], child2: [{ _type: "EntityChild2", name: "Test333", _id: 3, child2_child1: [{ _type: "EntityChild2_1", name: "Test444", _id: 6, child2_child1_child1: [{ _type: "EntityChild2_1_1", name: "Test555", _id: 7 }] }] }], _type: "EntityParent", name: "Test000", _id: 1, child3: [{ _type: "EntityChild3", name: "Test111", _id: 4 }], child4: [{ _type: "EntityChild4", name: "Test666", _id: 5 }] }],
flat = getFlat(data, -1);
console.log(flat);
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