python练手遇到的一个问题写了个统一公式，不用麻烦的分各种类，如果有人测试出错误请评论通知。
#分单双月
def dayNum(month,day,isLeap):
if month % 2 != 0:
if month == 1:
days = day
else:
days = (month - 1) * 30.5 - 2 + (month // 9) + day + isLeap
else:
if month == 2:
days = 31 + day
else:
days = (month - 1) * 30.5 - 1.5 + day + isLeap
return days
# 归类统一不分单双月
def dayNumPro(month,day,isLeap):
#月份大于九月时会出现差异
num = ((month // 9) and (month % 2 != 0))
if month == 1:
days = day
elif month == 2:
days = 31 + day
else:
days = (month - 1) * 30.5 - 1.5 - (month % 2)*0.5 + day + isLeap + num
return days def dayOfYear():
year = int(input("请输入年份:"))
month = int(input("请输入月份:"))
day = int(input("请输入日:"))
#判断是否是闰年(取真假1，0来参与运算不用分类)
isLeap = (year % 4 == 0) and (year % 400 != 0)
days = dayNumPro(month,day,isLeap)
print(days)
dayOfYear()