[HDOJ2586]How far away?(最近公共祖先, 离线tarjan, 并查集)

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2586

这题以前做过…现在用tarjan搞一发…竟然比以前暴力过的慢…………

由于是离线算法,需要Query来保存查询数据,Ans来保存结果。最后输出的时候按照idx的顺序输出,所以胡搞了个排序。。

dfs每次更新depth,当前点depth是上一个点累积下来的。

 /*
━━━━━┒ギリギリ♂ eye!
┓┏┓┏┓┃キリキリ♂ mind!
┛┗┛┗┛┃\○/
┓┏┓┏┓┃ /
┛┗┛┗┛┃ノ)
┓┏┓┏┓┃
┛┗┛┗┛┃
┓┏┓┏┓┃
┛┗┛┗┛┃
┓┏┓┏┓┃
┛┗┛┗┛┃
┓┏┓┏┓┃
┃┃┃┃┃┃
┻┻┻┻┻┻
*/
#include <algorithm>
#include <iostream>
#include <iomanip>
#include <cstring>
#include <climits>
#include <complex>
#include <fstream>
#include <cassert>
#include <cstdio>
#include <bitset>
#include <vector>
#include <deque>
#include <queue>
#include <stack>
#include <ctime>
#include <set>
#include <map>
#include <cmath> using namespace std; #define fr first
#define sc second
#define cl clear
#define BUG puts("here!!!")
#define W(a) while(a--)
#define pb(a) push_back(a)
#define Rint(a) scanf("%d", &a)
#define Rll(a) scanf("%lld", &a)
#define Rs(a) scanf("%s", a)
#define Cin(a) cin >> a
#define FRead() freopen("in", "r", stdin)
#define FWrite() freopen("out", "w", stdout)
#define Rep(i, len) for(int i = 0; i < (len); i++)
#define For(i, a, len) for(int i = (a); i < (len); i++)
#define Cls(a) memset((a), 0, sizeof(a))
#define Clr(a, x) memset((a), (x), sizeof(a))
#define Full(a) memset((a), 0x7f7f, sizeof(a))
#define lrt rt << 1
#define rrt rt << 1 | 1
#define pi 3.14159265359
#define RT return
typedef long long LL;
typedef long double LD;
typedef unsigned long long ULL;
typedef pair<int, int> pii;
typedef pair<string, int> psi;
typedef map<string, int> msi;
typedef vector<LL> vl;
typedef vector<vl> vvl;
typedef vector<bool> vb; typedef struct Query {
int idx;
int u, v;
Query() {}
Query(int uu, int vv, int ii) : u(uu), v(vv), idx(ii) {}
}Query; typedef struct Edge {
int v, w;
Edge() {}
Edge(int vv, int ww) : v(vv), w(ww) {}
}Edge; typedef struct Ans {
int idx;
int ans;
Ans() {}
Ans(int aa, int ii) :ans(aa), idx(ii) {}
}Ans; const int maxn = ;
const int maxm = ;
int n, m, qcnt, acnt;
int depth[maxn];
int in[maxn];
bool vis[maxn];
int pre[maxn];
Query q[maxm];
Ans ans[maxn];
vector<Edge> G[maxn];
int u, v, w; int find(int x) {
return x == pre[x] ? x : pre[x] = find(pre[x]);
} void unite(int x, int y) {
x = find(x);
y = find(y);
if(x != y) pre[y] = x;
} void dfs(int u, int d) {
// pre[u] = u;
depth[u] = d;
Rep(i, G[u].size()) {
int v = G[u][i].v;
if(!vis[v]) {
dfs(v, d+G[u][i].w);
unite(u, v);
}
}
vis[u] = ;
Rep(i, qcnt) {
int uu = q[i].u;
int vv = q[i].v;
int idx = q[i].idx;
if(vis[uu] && vv == u) {
ans[acnt].idx = idx;
ans[acnt++].ans = abs(depth[vv] - depth[uu]);
}
if(vis[vv] && uu == u) {
ans[acnt].idx = idx;
ans[acnt++].ans = abs(depth[uu] - depth[vv]);
}
}
} bool cmp(Ans x, Ans y) {
return x.idx < y.idx;
} int main() {
// FRead();
int T;
Rint(T);
W(T) {
Rint(n); Rint(m);
Cls(vis); Cls(depth); Cls(ans); Cls(G);
acnt = qcnt = ; Rep(i, n+) G[i].cl(), pre[i] = i;
Rep(i, n-) {
Rint(u); Rint(v); Rint(w);
G[u].push_back(Edge(v, w));
in[v]++;
}
Rep(i, m) {
Rint(u); Rint(v);
q[qcnt++] = Query(u, v, i);
}
For(i, , n+) if(in[i] == ) dfs(i, );
sort(ans, ans+acnt, cmp);
Rep(i, acnt) {
printf("%d\n", ans[i].ans);
}
}
RT ;
}
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