D. Divide and Summarize

题意

给你n个数，q次询问，问你能否具有满足和为s的序列。

思路

再求其有多少种和时需要使用\(mid = max + min >> 1\)来寻找有多少种和。

然后dfs，但是需要判断一下左面或者右面全部相等情况，否则会爆栈

#include<bits/stdc++.h>
using namespace std;
const int N = 2e5 + 100;
typedef long long LL;
//#define int long long

int a[N];int n, q;
set<LL>ans;
LL sum[N];
void dfs(int l ,int r) {
	if (l > r) return;
	ans.insert(sum[r] - sum[l - 1]);
	if (a[l] == a[r]) {
		return;
	}
	int mid = a[l] + a[r] >> 1;
	int idx = upper_bound(a + l, a + 1 + r, mid) - a;
	dfs(l, idx - 1);
	dfs(idx, r);
}

void solve() {
	ans.clear();
	cin >> n >> q;
	for (int i  = 1; i <= n; ++i)cin >> a[i];
	sort(a + 1, a + 1 + n);
	for (int i = 1; i <= n; ++i) sum[i] = sum[i - 1] + a[i];

	dfs(1 ,n);
	while (q--) {
		LL s; cin >> s;

		if (ans.count(s)) cout << "YES\n";
		else cout << "NO\n";
	}
}
signed main() {
	ios::sync_with_stdio(0);
	cin.tie(0);
	int T = 1;
	 cin >> T;
	while (T--) {
		solve();
	}

}