【数学建模】基于matlab模拟十字路口车辆通行【含Matlab源码 1106期】

## 一、简介 基于matlab模拟十字路口车辆通行: 用matlab模拟出十字路口的车辆通行情况,车流量可以自己设置,并且绘出了图象能直观地模拟出十字路口的通行状况。 ## 二、源代码 ```c clear;clc; width=30 %道路宽 rl=5*width/8; %左转虚拟车道 rr=1*width/8; %右转虚拟车道 drr=pi/2*rr; dstr=width-sqrt(rl^2-(width/8)^2); %直行距离 dl=(acos(width/8/rl))*rl; %左拐距离 ck=1.8 ; %车宽 cl=3.8 ; %车长 ddstr=sqrt((rl+ck/2)^2-(width/8+ck/2)^2)-sqrt(rl^2-(width/8)^2); ddl=(acos(width/8/rl)-acos((width/8+ck/2)/(rl+ck/2)))*rl; sl=dl; sstr=dstr; onetime=160; dmin=2; azb=[]; bzb=[]; alcar=[]; %行车矩阵 arcar=[]; astrcar=[]; blcar=[]; brcar=[]; bstrcar=[]; cjjlal=[]; cjjlar=[]; cjjlastr=[];%车间距 cjjlbl=[]; cjjlbr=[]; cjjlbstr=[];%车间距 red=30; yel=10; val0=4 ; %a左行车速度(此处设未冲突速度) var0=5 ; %a右行车速度(此处设未冲突速度) vastr0=6 ; %a直行车速度(此处设未冲突速度) vbl0=val0 ; %b左行车速度(此处设未冲突速度) vbr0=var0 ; %b右行车速度(此处设未冲突速度) vbstr0= vastr0 ; %b直行车速度(此处设未冲突速度) val=[]; val(1)=val0 ; var=[]; var(1)=var0 ; vastr=[] ; vastr(1)=vastr0; vbl=[] ; vbl(1)=vbl0; vbr=[]; vbr(1)=vbr0 ; vbstr=[] vbstr(1)=vbstr0 ; dt=0.1 ; %时间步长 alcar(1)=val*dt; arcar(1)=vbr(1)*dt; astrcar(1)=vastr(1)*dt; blcar(1)=vbl(1)*dt; brcar(1)=vbr(1)*dt; bstrcar(1)=vbstr(1)*dt; T=dt; sumal=1; sumar=1; sumastr=1; sumbl=1; sumbr=1; sumbstr=1; kal=1; kar=1; kastr=1; kbl=1; kbr=1; kbstr=1; dertal=0; dertas=0; %外部条件参数=========================================================================================================== yctime=0.5;%加速延迟时间 jsxs=0.7;%减速系数 ajia=8;%最大加速度 ajian=8;%最大减速度 azxgl=1; ayzxgl=1; bzxgl=1; byzxgl=1; pro=0.02; sigma=1; n=20;%画图中的模拟车!!!!!!!!!!!!!!!!!!!!! ttt=0.000000001; while T<=onetime T=T+dt; lor=mod(floor(T/(red+yel)),2); goy=mod(T,red+yel); %虚拟交警================================================================================================================ if kal~=0 cjjlal(1)=0;%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%555 end if kar~=0 cjjlar(1)=0;%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%555 end if kastr~=0 cjjlastr(1)=0;%%%%%%%%%%%%%%%%%%%%%%5 end if kbl~=0 cjjlbl(1)=0;%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%555 end if kbr~=0 cjjlbr(1)=0;%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%555 end if kbstr~=0 cjjlbstr(1)=0;%%%%%%%%%%%%%%%%%%%%%%5 end if kbl~=0&&kastr~=0 pbl=dl-blcar(1)-sl; pastr=dstr-astrcar(1)-sstr; if pbl<=0&&pastr<=0 ttsl=(dl-blcar(1)-ddl)/vbl(1)+dertal; ttsstr=(dstr-astrcar(1)-ddstr)/vastr(1)+dertas; if(ttsstr<=ttsl) if vastr(1)ttsl) if vbl(1)ttsl) if val(1)
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