django2.2连oracle11g解决版本冲突问题

2022-11-02 22:27:23

上次用django2.2和oracle11g，在migrate的时候发生了版本冲突，最终将Oracle升级到了12c才解决问题

那么到底能不能用别的方法来解决这个冲突呢？想了个解决思路，实践一下：

  1. 用django2.2连Oracle12c环境下做migrate，创建基础表
  2. 将基础表导出，再导入到Oracle11g数据库中
  3. 用django2.2连Oracle11g

实施步骤

1、用django2.2连Oracle12c环境下做migrate，创建基础表

在前文中已经完成，连接到数据库，可以看到有10张基础表
django2.2连oracle11g解决版本冲突问题
看一张表，比如AUTH_GROUP表，发现有个ID字段是用了12c特有的generated语法，除了DJANGO_SESSION外，其他每张表都有一个自增序列的id字段作为主键。

-- Create table
create table AUTH_GROUP
(
  id   NUMBER(11) generated by default on null as identity,
  name NVARCHAR2(150)
)
tablespace DJANGO;
-- Create/Recreate primary, unique and foreign key constraints 
alter table AUTH_GROUP
  add primary key (ID)
  using index 
  tablespace DJANGO;
alter table AUTH_GROUP
  add unique (NAME)
  using index 
  tablespace DJANGO;

2. 将基础表导出，再导入到Oracle11g数据库中

导出django用户数据库，注意使用11g版本
django2.2连oracle11g解决版本冲突问题
接着导入到11g数据库中，非常顺利
django2.2连oracle11g解决版本冲突问题
再看AUTH_GROUP表，发现表结构是一样的，但是id上面自增序列的默认值没有了。

-- Create table
create table AUTH_GROUP
(
  id   NUMBER(11) not null,
  name NVARCHAR2(150)
)
tablespace DJANGO;
-- Create/Recreate primary, unique and foreign key constraints 
alter table AUTH_GROUP
  add primary key (ID)
  using index 
  tablespace DJANGO;
alter table AUTH_GROUP
  add unique (NAME)
  using index 
  tablespace DJANGO;

3、用django2.2连Oracle11g

修改settings文件，连Oracle11g，然后启动django服务，果然成功启动
django2.2连oracle11g解决版本冲突问题
django2.2连oracle11g解决版本冲突问题
但是，但是，创建admin用户密码的时候就报错了，ORA-01400: cannot insert NULL into (“DJANGO”.“AUTH_USER”.“ID”)

PS D:\parttime\python\django\guanxiangzhiji> python manage.py createsuperuser
用户名 (leave blank to use 'administrator'):
电子邮件地址:
Password:
Password (again):
密码长度太短。密码必须包含至少 8 个字符。
这个密码太常见了。
Bypass password validation and create user anyway? [y/N]: y
Traceback (most recent call last):
  File "D:\app\anaconda\lib\site-packages\django\db\backends\utils.py", line 84, in _execute
    return self.cursor.execute(sql, params)
  File "D:\app\anaconda\lib\site-packages\django\db\backends\oracle\base.py", line 510, in execute
    return self.cursor.execute(query, self._param_generator(params))
cx_Oracle.IntegrityError: ORA-01400: cannot insert NULL into ("DJANGO"."AUTH_USER"."ID")

The above exception was the direct cause of the following exception:

Traceback (most recent call last):
  File "manage.py", line 21, in <module>
    main()
  File "manage.py", line 17, in main
    execute_from_command_line(sys.argv)
  File "D:\app\anaconda\lib\site-packages\django\core\management\__init__.py", line 381, in execute_from_command_line
    utility.execute()
  File "D:\app\anaconda\lib\site-packages\django\core\management\__init__.py", line 375, in execute
    self.fetch_command(subcommand).run_from_argv(self.argv)
  File "D:\app\anaconda\lib\site-packages\django\core\management\base.py", line 323, in run_from_argv
    self.execute(*args, **cmd_options)
  File "D:\app\anaconda\lib\site-packages\django\contrib\auth\management\commands\createsuperuser.py", line 61, in execute
    return super().execute(*args, **options)
  File "D:\app\anaconda\lib\site-packages\django\core\management\base.py", line 364, in execute
    output = self.handle(*args, **options)
  File "D:\app\anaconda\lib\site-packages\django\contrib\auth\management\commands\createsuperuser.py", line 156, in handle
    self.UserModel._default_manager.db_manager(database).create_superuser(**user_data)
  File "D:\app\anaconda\lib\site-packages\django\contrib\auth\models.py", line 162, in create_superuser
    return self._create_user(username, email, password, **extra_fields)
  File "D:\app\anaconda\lib\site-packages\django\contrib\auth\models.py", line 145, in _create_user
    user.save(using=self._db)
  File "D:\app\anaconda\lib\site-packages\django\contrib\auth\base_user.py", line 66, in save
    super().save(*args, **kwargs)
  File "D:\app\anaconda\lib\site-packages\django\db\models\base.py", line 741, in save
    force_update=force_update, update_fields=update_fields)
  File "D:\app\anaconda\lib\site-packages\django\db\models\base.py", line 779, in save_base
    force_update, using, update_fields,
  File "D:\app\anaconda\lib\site-packages\django\db\models\base.py", line 870, in _save_table
    result = self._do_insert(cls._base_manager, using, fields, update_pk, raw)
  File "D:\app\anaconda\lib\site-packages\django\db\models\base.py", line 908, in _do_insert
    using=using, raw=raw)
  File "D:\app\anaconda\lib\site-packages\django\db\models\manager.py", line 82, in manager_method
    return getattr(self.get_queryset(), name)(*args, **kwargs)
  File "D:\app\anaconda\lib\site-packages\django\db\models\query.py", line 1186, in _insert
    return query.get_compiler(using=using).execute_sql(return_id)
  File "D:\app\anaconda\lib\site-packages\django\db\models\sql\compiler.py", line 1335, in execute_sql
    cursor.execute(sql, params)
  File "D:\app\anaconda\lib\site-packages\django\db\backends\utils.py", line 99, in execute
    return super().execute(sql, params)
  File "D:\app\anaconda\lib\site-packages\django\db\backends\utils.py", line 67, in execute
    return self._execute_with_wrappers(sql, params, many=False, executor=self._execute)
  File "D:\app\anaconda\lib\site-packages\django\db\backends\utils.py", line 76, in _execute_with_wrappers
    return executor(sql, params, many, context)
  File "D:\app\anaconda\lib\site-packages\django\db\backends\utils.py", line 84, in _execute
    return self.cursor.execute(sql, params)
  File "D:\app\anaconda\lib\site-packages\django\db\utils.py", line 89, in __exit__
    raise dj_exc_value.with_traceback(traceback) from exc_value
  File "D:\app\anaconda\lib\site-packages\django\db\backends\utils.py", line 84, in _execute
    return self.cursor.execute(sql, params)
  File "D:\app\anaconda\lib\site-packages\django\db\backends\oracle\base.py", line 510, in execute
    return self.cursor.execute(query, self._param_generator(params))
django.db.utils.IntegrityError: ORA-01400: cannot insert NULL into ("DJANGO"."AUTH_USER"."ID")

原因分析
很明显，插入到AUTH_USER表时，没有指定ID的值，而ID是主键，非空。
因为在12c的环境下，这个ID是自增序列，insert语句中不需要指定这个值。

解决方案
解决方案也应运而出了，只要为每个ID列创建一个11g的序列，创建触发器，在插入数据时补上id值就行了。
（1）生成序列。
用sql语句

select 'create sequence seq_'||table_name||' minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;'
  from user_tab_columns
  where column_name='ID';

生成创建序列的批量执行语句，并执行。

create sequence seq_DJANGO_ADMIN_LOG minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;
create sequence seq_AUTH_USER minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;
create sequence seq_AUTH_USER_GROUPS minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;
create sequence seq_DJANGO_CONTENT_TYPE minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;
create sequence seq_AUTH_GROUP minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;
create sequence seq_AUTH_GROUP_PERMISSIONS minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;
create sequence seq_DJANGO_MIGRATIONS minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;
create sequence seq_AUTH_PERMISSION minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;
create sequence seq_AUTH_USER_USER_PERMISSIONS minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;

（2）创建触发器
用SQL语句

select 'create or replace trigger tri_'||table_name||'
					before insert
					on '||table_name||' 
					for each row
				declare
				begin
					:new.id:=seq_'||table_name||'.nextval;
				end tri_'||table_name||';
				/'
  from user_tab_columns
  where column_name='ID';

生成触发器脚本：

create or replace trigger tri_DJANGO_MIGRATIONS
	before insert
	on DJANGO_MIGRATIONS
	for each row
declare
begin
	:new.id:=seq_DJANGO_MIGRATIONS.nextval;
end tri_DJANGO_MIGRATIONS;
/
create or replace trigger tri_DJANGO_CONTENT_TYPE
	before insert
	on DJANGO_CONTENT_TYPE
	for each row
declare
begin
	:new.id:=seq_DJANGO_CONTENT_TYPE.nextval;
end tri_DJANGO_CONTENT_TYPE;
/
create or replace trigger tri_AUTH_PERMISSION
	before insert
	on AUTH_PERMISSION
	for each row
declare
begin
	:new.id:=seq_AUTH_PERMISSION.nextval;
end tri_AUTH_PERMISSION;
/
create or replace trigger tri_AUTH_GROUP
	before insert
	on AUTH_GROUP
	for each row
declare
begin
	:new.id:=seq_AUTH_GROUP.nextval;
end tri_AUTH_GROUP;
/
create or replace trigger tri_AUTH_GROUP_PERMISSIONS
	before insert
	on AUTH_GROUP_PERMISSIONS
	for each row
declare
begin
	:new.id:=seq_AUTH_GROUP_PERMISSIONS.nextval;
end tri_AUTH_GROUP_PERMISSIONS;
/
create or replace trigger tri_AUTH_USER
	before insert
	on AUTH_USER
	for each row
declare
begin
	:new.id:=seq_AUTH_USER.nextval;
end tri_AUTH_USER;
/
create or replace trigger tri_AUTH_USER_GROUPS
	before insert
	on AUTH_USER_GROUPS
	for each row
declare
begin
	:new.id:=seq_AUTH_USER_GROUPS.nextval;
end tri_AUTH_USER_GROUPS;
/
create or replace trigger tri_AUTH_USER_USER_PERMISSIONS
	before insert
	on AUTH_USER_USER_PERMISSIONS
	for each row
declare
begin
	:new.id:=seq_AUTH_USER_USER_PERMISSIONS.nextval;
end tri_AUTH_USER_USER_PERMISSIONS;
/
create or replace trigger tri_DJANGO_ADMIN_LOG
	before insert
	on DJANGO_ADMIN_LOG
	for each row
declare
begin
	:new.id:=seq_DJANGO_ADMIN_LOG.nextval;
end tri_DJANGO_ADMIN_LOG;
/

（3）此时再创建admin用户，就成功了
django2.2连oracle11g解决版本冲突问题
django2.2连oracle11g解决版本冲突问题
新增用户lurenjia成功！
django2.2连oracle11g解决版本冲突问题

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