BZOJ原题链接
洛谷原题链接
简单的数位\(DP\),套模板就好。
#include<cstdio>
#include<cstring>
using namespace std;
const int N = 15;
int f[N][N], a[N];
inline int re()
{
int x = 0;
char c = getchar();
bool p = 0;
for (; c < '0' || c > '9'; c = getchar())
p |= c == '-';
for (; c >= '0' && c <= '9'; c = getchar())
x = x * 10 + c - '0';
return p ? -x : x;
}
inline int jd(int x){ return x < 0 ? -x : x; }
int dfs(int pos, int pre, int lm, int zero)
{
if (pos < 0)
return 1;
if (pre > 0 && !lm && !zero && f[pos][pre] > -1)
return f[pos][pre];
int i, k = lm ? a[pos] : 9, su = 0;
for (i = 0; i <= k; i++)
if (jd(i - pre) > 1)
su += dfs(pos - 1, zero && !i ? -2 : i, lm && i == a[pos], zero && !i);
if (pre > 0 && !lm && !zero)
return f[pos][pre] = su;
return su;
}
int calc(int x)
{
int l = 0;
while (x > 0)
{
a[l++] = x % 10;
x /= 10;
}
return dfs(l - 1, -2, 1, 1);
}
int main()
{
int x, y;
x = re();
y = re();
memset(f, -1, sizeof(f));
printf("%d", calc(y) - calc(x - 1));
return 0;
}