Censor
frog is now a editor to censor so-called sensitive words (敏感词).
She has a long text \(p\). Her job is relatively simple -- just to find the first occurence of sensitive word \(w\) and remove it.
frog repeats over and over again. Help her do the tedious work.
Input
The input consists of multiple tests. For each test:
The first line contains \(1\) string \(w\). The second line contains \(1\) string \(p\).
(\(1 \leq \textrm{length of}\ w, p \leq 5 \cdot 10^6\), \(w, p\) consists of only lowercase letter)
Output
For each test, write \(1\) string which denotes the censored text.
Sample Input
abc
aaabcbc
b
bbb
abc
abSample Output
a
ab题目链接：SCU 4438
用哈希来做的话比KMP简单很多，每一次加入一个字符，看倒数Len个字符的哈希值是否和模式串相同，若相同则弹出Len个元素，否则再加入元素并更新哈希值
代码：
#include <stdio.h>
#include <bits/stdc++.h>
using namespace std;
#define INF 0x3f3f3f3f
#define LC(x) (x<<1)
#define RC(x) ((x<<1)+1)
#define MID(x,y) ((x+y)>>1)
#define CLR(arr,val) memset(arr,val,sizeof(arr))
#define FAST_IO ios::sync_with_stdio(false);cin.tie(0);
typedef pair<int, int> pii;
typedef unsigned long long ULL;
const double PI = acos(-1.0);
const int N = 5e6 + 7;
const ULL seed = 1e9 + 7;
char w[N], p[N], ans[N];
int lw, lp;
ULL prefix[N] = {1ull}, st[N]; ULL gethash(char s[], int len)
{
ULL hashval = 0ull;
for (int i = 0; i < len; ++i)
hashval = hashval * seed + s[i];
return hashval;
} int main(void)
{
int i;
for (i = 1; i < N; ++i)
prefix[i] = prefix[i - 1] * seed;
while (~scanf("%s%s", w, p))
{
lw = strlen(w);
lp = strlen(p);
ULL tar = gethash(w, lw);
int top = 0;
st[top] = 0;
for (i = 0; i < lp; ++i)
{
ans[top++] = p[i];
st[top] = st[top - 1] * seed + p[i];
if (top >= lw && st[top] - st[top - lw]*prefix[lw] == tar)
top -= lw;
}
ans[top] = '\0';
printf("%s\n", ans);
}
return 0;
}