java中HashMap的基本方法使用

遍历,添加词,等等

package test;
import java.util.HashMap;
import java.util.Iterator;
import java.util.ArrayList;
import java.util.Collection;
import java.util.Map.Entry;
import java.util.Set;
public class test6 { public static void main(String[] args) {
HashMap<String,Integer> map =new HashMap<>();
map.put("a", 1);
map.put("b", 2);
map.put("c", 3);
map.put("d", 4); // Map map=new HashMap();
// map.put("a", "aaa");
// map.put("b", "bbb");
// map.put("c", "ccc");
// map.put("d", "ddd"); //hashMap遍历方法1
Iterator<String> iterator = map.keySet().iterator();
while (iterator.hasNext()) {
Object key = iterator.next();
System.out.println("map.get(key) is :"+map.get(key));
} //遍历方法2
Set<Map.Entry<String, Integer>> set=map.entrySet();
Iterator<Map.Entry<String, Integer>> it=set.iterator();
while(it.hasNext()){
//System.out.println(list.get(0) );
Map.Entry<String, Integer> e=it.next();
System.out.println(e.getKey()+":"+e.getValue());
} System.out.println(map.containsValue(1) );
System.out.println(map.containsKey("a") );
System.out.println(map.size() );
System.out.println(map.remove("a") );
System.out.println(map.size() );
System.out.println(map.containsKey("a") );
System.out.println(map.containsValue(1) ); //ArrayList <Integer> list =(ArrayList<Integer>)map.values();
//上面会出现异常,因为map.values()返回的是一个Collection<Integer>对象,可用下面的方法解决
ArrayList <Integer> list =new ArrayList<Integer>(map.values());
Iterator <Integer>ite=list.iterator();
while(ite.hasNext()){
//System.out.println(list.get(0) );
System.out.println(ite.next() );
}
map.clear();
System.out.println(map.isEmpty() ); } }

  

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