--用json的时候，知道id获取对应的name或者相反根据name获取id
--内核代码
<script>
var products=[{ID:1,Name:"a",Price:1},{ID:2,Name:"b",Price:4}];
for(var s in products)
{ alert("ID是："+products[s].ID+"Name是："+products[s].Name); }
</script>
products[索引]获得json数组对象，然后 对象.属性 获得属性值。
--两个方法：
--1、idToName
function idToName(jsonList,id)
{
var schools = jsonList[0].school;
var name = '';
for(var s in schools) {
var getId = schools[s].id ;
var getName = schools[s].name;
if (getId = id ) name = getName ;
};
return name ;
}
--2、nameToId
function nameToId(jsonList,name)
{
var schools = jsonList[0].school;
var id = '';
//alert(name);
for(var s in schools) {
var getId = schools[s].id ;
var getName = schools[s].name;
//alert('getId='+getId);
//alert('gegName='+getName);
//alert (getName + name);
//alert (getName == name);
if (getName == name ) {
id = getId;
//alert('findid='+id);
return id;
} ;
};
}