JavaWeb 发送get请求
CreationTime--2018年6月20日15点27分
Author:Marydon
1.前提
通过HttpClient来实现
2.具体实现
客户端如何发送请求？
所需jar包：
commons-httpclient-3.0.jar
commons-codec-1.9.jar
commons-logging-1.1.1.jar
导入
import org.apache.commons.httpclient.HttpClient;
import org.apache.commons.httpclient.HttpStatus;
import org.apache.commons.httpclient.methods.GetMethod;
/**
* 发送get请求
* @explain
* 1.请求体：get传参没有请求体
* 2.数据格式：直接拼接到url后面，如：url?key1=value1&key2=value2&...
* @param url 路径及参数
* @return 服务器返回数据
*/
public static String sendGet(String url) {
// 用于接收返回的结果
String resultData = "";
try {
HttpClient httpClient = new HttpClient();
httpClient.getHttpConnectionManager().getParams().setConnectionTimeout(3000); // 设置连接超时
httpClient.getHttpConnectionManager().getParams().setSoTimeout(180000); // 设置读取数据超时
httpClient.getParams().setContentCharset("UTF-8");
GetMethod get = new GetMethod(url);
int status = httpClient.executeMethod(get);
// 状态码为：200
if (status == HttpStatus.SC_OK) {
resultData = get.getResponseBodyAsString();
} else {
throw new RuntimeException("接口连接失败！");
}
} catch (Exception e) {
e.printStackTrace();
throw new RuntimeException("接口连接失败！");
}
return resultData;
}
服务器端如何接收客户端传递的数据？
request.getParameter("key")
3.客户端调用测试
public static void main(String[] args) {
String requestUrl = "http://localhost:8070/test/rz/server/rzxx/at_VaildToken.do?un_value=B022420184794C7C9D5096CC5F3AE7D2";
// 发送post请求并接收返回结果
String resultData = sendGet(requestUrl);
System.out.println(resultData);
}