Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input Specification:
Each input file contains one test case. Each case contains a pair of integers a and b where −. The numbers are separated by a space.
Output Specification:
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input:
-1000000 9
Sample Output:
#include<bits/stdc++.h> using namespace std; #define _for(i, a, b) for (int i = (a); i <= (b); i++) int main() { char s[15], rs[15]; int a, b, c; cin >> a >> b; c = a + b; sprintf(s,"%d",c); int len = strlen(s); for (int i = 0; i < len;i++){ printf("%c", s[i]); if(s[0]=='-'){ if((i)%3==(len-1)%3&&i!=len-1&&i!=0){ printf(","); } }else{ if ((i+1) % 3 == len % 3 && i != len - 1) { printf(","); } } } puts(""); return 0; }-999,991
长度余3的地方插进去一个逗号,正数的话i要加1,负号占了一个下标不用加。数字的最后面和最前面也不用加逗号。