在Asp.Net MVC中实现上传图片并显示

2022-10-25 13:13:31

实现思路大概分为两步：

1. 通过上传接口，将图片上传到服务器，返回文件路径给客户端；

2. 点击保存上传，将文件路径保存到数据库，如果是多张图片，路径用逗号分隔。

核心上传代码：

        /// <summary>

        /// 图片上传

        /// </summary>

        /// <returns></returns>

        [HttpPost]

        [Route("PostFile")]

        public HttpResponseMessage PostFile()

        {

            //TODO:Save file...

            if (!Request.Content.IsMimeMultipartContent("form-data"))

                throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType);

            HttpResponseMessage response = null;

            HttpContext context = HttpContext.Current;

            try

            {

                HttpPostedFile file = HttpContext.Current.Request.Files["form-data"];

                if (!string.IsNullOrEmpty(context.Request["type"]))

                {

                    string type = context.Request["type"].ToString();

                    if (type == "image")

                    {

                        if (!string.IsNullOrEmpty(context.Request["size"]))

                        {

                            string sizes = context.Request["size"].ToString();

                            response = Request.CreateResponse(HttpStatusCode.Accepted, SaveBySize(file, sizes.Split(',')));

                        }

                        else

                        {

                            context.Response.Write("{ret:-1,msg:\"参数错误\"}");

                        }

                    }

                    else

                    {

                        response = Request.CreateResponse(HttpStatusCode.Accepted, Save(file));

                    }

                }

                else

                {

                    response = Request.CreateResponse(HttpStatusCode.Accepted, Save(file));

                }

            }

            catch (HttpResponseException ex)

            {

                //throw new HttpResponseException(HttpStatusCode.BadRequest);

                response = Request.CreateErrorResponse(HttpStatusCode.ExpectationFailed, ex.ToString());

            }

            return response;

        }