题目链接:https://www.luogu.org/problemnew/show/P1903
裸的。。。带修莫队。。。
比较麻烦吧(对我来说是的)
两个变量分开记录查询和修改操作。
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#define ri register
using namespace std;
const int maxn = ;
int n, m, bl, answer = , qnum = , unum = , curR, curL, now;
int ans[maxn],a[maxn],cnt[maxn];
struct query{
int l, r, p, t;
bool operator < (const query &x) const {
if(l / bl != x.l / bl) return l / bl < x.l / bl;
if(r / bl != x.r / bl) return r / bl < x.r / bl;
return t < x.t;
}
}q[maxn];
struct update{
int pos, val;
}u[maxn];
inline void add(int pos) {
if(++ cnt[pos] == ) answer ++;
}
inline void remove(int pos) {
if(-- cnt[pos] == ) answer --;
}
inline void change(int now, int i) {
if(q[i].l <= u[now].pos && u[now].pos <= q[i].r) {
if( --cnt[a[u[now].pos]] == ) answer--;
if( ++cnt[u[now].val] == ) answer++;
}
swap(a[u[now].pos], u[now].val);
}
int main()
{
scanf("%d%d",&n,&m);
bl = pow(n,1.0/);
for(ri int i = ; i <= n; i++)
scanf("%d",&a[i]);
for(ri int i = ; i <= m; i++)
{
int ch, x, y;
while((ch = getchar()) != 'Q' && ch != 'R');
scanf("%d%d", &x, &y);
if(ch == 'Q') {
q[++ qnum].l = x;
q[qnum].r = y;
q[qnum].t = unum;
q[qnum].p = qnum;
} else {
u[++unum].pos = x;
u[unum].val = y;
}
}
sort(q+,q+qnum+);
curL = q[].l, curR = curL - , now = ;
for(ri int i = ; i <= qnum; i ++) {
while(curL < q[i].l) remove(a[curL ++]);
while(curL > q[i].l) add(a[-- curL]);
while(curR < q[i].r) add(a[++ curR]);
while(curR > q[i].r) remove(a[curR --]);
while(now < q[i].t) change(++ now, i);
while(now > q[i].t) change(now --, i);
ans[q[i].p] = answer;
}
for(ri int i = ; i <= qnum; i++)
printf("%d\n",ans[i]);
return ;
}