经纬度计算两点间的距离,根据距离排序SQL

#java的Utils
public class DistanceUtil { // 地球平均半径
private static final double EARTH_RADIUS = 6378137; // 把经纬度转为度(°)
private static double rad(double d) {
return d * Math.PI / 180.0;
} /**
* 根据两点间经纬度坐标(double值),计算两点间距离,单位:千米
* @author ershuai
* @param lng1
* @param lat1
* @param lng2
* @param lat2
* @return
*/
public static double getDistance(double lng1, double lat1, double lng2, double lat2) {
double radLat1 = rad(lat1);
double radLat2 = rad(lat2);
double a = radLat1 - radLat2;
double b = rad(lng1) - rad(lng2);
double s = 2 * Math.asin(Math.sqrt(Math.pow(Math.sin(a / 2), 2) + Math.cos(radLat1) * Math.cos(radLat2) * Math.pow(Math.sin(b / 2), 2)));
s = s * EARTH_RADIUS;
s = s / 1000;
DecimalFormat df = new DecimalFormat("#.00");
s = Double.parseDouble(df.format(s));
return s;
} public static void main(String[] args) {
double distance1 = getDistance(104.046115, 30.6030110000, 104.074666, 30.611842);
System.out.println("Distance is: " + distance1 + " km");
}
} #SQL SELECT
es_name,
es_lon,
es_lat,
ROUND(
6378.138 * 2 * ASIN(
SQRT(
POW(
SIN(
(
30.611842 * PI() / 180 - es_lat * PI() / 180
) / 2
),
2
) + COS(30.611842 * PI() / 180) * COS(es_lat * PI() / 180) * POW(
SIN(
(
104.074666 * PI() / 180 - es_lon * PI() / 180
) / 2
),
2
)
)
) * 1000
) AS distance_um
FROM
c_ershuai
ORDER BY
distance_um ASC

  转自:https://www.cnblogs.com/dcxmaozi/p/6921407.html

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