最近又开始使用XML了，但今天遇到一个折腾我一下午加一个晚上的时间，终于从网络上找到相关的资料解决了。
有一个成员是用来存放正则表达式的，由于里面包含其它字符，所以想用CDATA来保存方便查看，所以想到另建一个类再通过继承IXmlSerializable 接口来实现CDATA节点。参照了官方MSDN文档，写了类似以下的代码：
using System;
using System.Xml;
using System.Xml.Schema;
using System.Xml.Serialization;
using Microsoft.VisualStudio.TestTools.UnitTesting;
using System.IO;
using System.Diagnostics; namespace BeiBei.Core.Tests
{
[XmlRoot("Worker")]
public class Worker
{
[XmlElement]
public string JobTitle { get; set; } [XmlAttribute("active")]
public bool Active { get; set; } [XmlElement]
public string NextPageEncodingName { get; set; } [XmlElement]
public Person Person { get; set; } [XmlElement]
public Person Person2 { get; set; } } public class Person : IXmlSerializable
{
// Private state
private string personName; // Constructors
public Person(string name)
{
personName = name;
} public Person()
{
personName = null;
} // Xml Serialization Infrastructure
public void WriteXml(XmlWriter writer)
{
writer.WriteString(personName);
} public void ReadXml(XmlReader reader)
{
personName = reader.ReadString();
} public XmlSchema GetSchema()
{
return (null);
public override string ToString()
{
return (personName);
} } [TestClass]
public class IXmlSerializableTests
{
[TestMethod]
public void S_Person_Test()
{
var p = new Person("Shawn"); XmlSerializer serializer = new XmlSerializer(typeof(Person)); string path = "D:\\Test.Person.xml";
string path2 = "D:\\Test.Person.2.xml"; using (var writer = XmlWriter.Create(path))
{
serializer.Serialize(writer, p);
} using (var reader = XmlReader.Create(path))
{
var p2 = serializer.Deserialize(reader) as Person; using (var writer2 = XmlWriter.Create(path2))
{
serializer.Serialize(writer2, p2);
}
} var xml1 = File.ReadAllText(path);
var xml2 = File.ReadAllText(path2);
Assert.AreEqual(xml1, xml2);
Debug.WriteLine(xml2);
} [TestMethod]
public void S_Worker_Test()
{
var p = new Person("Shawn");
var pp = new Person("John"); var w = new Worker()
{
JobTitle = "Boss",
Person = p,
Person2 = pp,
NextPageEncodingName = "gb2312",
}; XmlSerializer serializer = new XmlSerializer(typeof(Worker)); string path = "D:\\Test.Worker.xml";
string path2 = "D:\\Test.Worker.2.xml"; using (var writer = XmlWriter.Create(path))
{
serializer.Serialize(writer, w);
} using (var reader = XmlReader.Create(path))
{
var w2 = serializer.Deserialize(reader) as Worker; using (var writer2 = XmlWriter.Create(path2))
{
serializer.Serialize(writer2, w2);
}
} var xml1 = File.ReadAllText(path);
var xml2 = File.ReadAllText(path2); Debug.WriteLine(xml2);
Assert.AreEqual(xml1, xml2);
}
}
}
结果Serialize出来的文件是正常的，但Deserialize后文件中，第一个Person之后的其它属性都没有了。
尝试了很多次，当个PERSON对象序列化/反序列化都是没有问题的，但当对象包括PERSON，且PERSON属性后还定义了其它的属性，尝试添加<XmlElement>之类的特性都没用。结论就是：第一个PERSON属性之后的其它属性一率都没能正常Deserialize。怪自己对这块不了解，更怪MSDN没有写好例子！
后来在这里找到答案：
http://www.codeproject.com/Articles/43237/How-to-Implement-IXmlSerializable-Correctly
其实跟属性顺序没有关系，而是我们没有把ReadXml的实现正确地实现了。再改成如下就正常了:
public void ReadXml(XmlReader reader)
{
reader.MoveToContent();
var isEmptyElement = reader.IsEmptyElement;
reader.ReadStartElement(); if (!isEmptyElement)
{
personName = reader.ReadString();
reader.ReadEndElement();
}
}
终于搞定了，终于可以继续后面的任务！刚过了十二点！