设计并验证以下算法：若矩阵采用三元组顺序表表示，设计并验证找出矩阵所有马鞍点的算法。

直接上代码： 

 

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define MAX 500
#define M 100
#define N 100

 
typedef int arr_type;

//储存行 列 值 
typedef struct {
	int row;//从1 开始 
	int col;//从1 开始 
	arr_type value;
}array;

//储存三元组顺序表+总行数，总列数，总非零元素个数 
typedef struct {
	array arr[MAX];//从0开始 
	int rownum,colnum,all;
}sparse_matrix;


//生成随机稀疏矩阵三元组 
arr_type  rand_array(sparse_matrix *s1){
	srand(time(NULL));
	int r1;
	r1 = s1->rownum * s1->colnum;
	int k;
	s1->all = 0;
	//矩阵A随机生成
	for(int i = 1;i <= s1->rownum;i++)
		for(int j = 1;j <= s1->colnum;j++)
		{
			k = rand()%r1;
			//printf("%d\n",k);
			if(k < (r1/10))
			{
				s1->arr[s1->all].value = (rand()%9)+1;
				s1->arr[s1->all].row = i;
				s1->arr[s1->all].col = j;
				s1->all++;
			}
		}
	if(r1/s1->all > 20)
		return 1;
	
	return 0;
}

int minn[M] = {0},maxx[N] = {0};
void MinMax(sparse_matrix *s)///M行中最小，N列中最大
{
    int i,j;
    int ord = 0,turn = 1;
    bool have = false;
    for(i=1; i <= s->rownum; i++) ///求出每行最小数，存在minn[0...M-1]中
    {
        while(s->arr[ord].row == i)
        {
        	if(turn == 1)
        		{
        			minn[i-1] = ord;
        			ord++;
					turn = 0;
					continue;
				}
			if(s->arr[minn[i-1]].value > s->arr[ord].value)
				minn[i-1] = ord;
        	ord++;
		}
		turn = 1;
    }
    
    ord = 0;
	for(j=1; j <= s->colnum; j++) ///求出每列最大数，存在maxx[0...N-1]中
    {
        //printf("%d",j);
		while(1)// (1,2) (1,4) (2,3) (3,3) (3,5) (5,1) ord=012345,colnum=5,j>0,s->all=6,
        {		//   0		1	2		3	4		5
        	while(s->arr[ord].col != j&&(ord < s->all))
	        {
	        	if(ord == s->all-1)
	        		break;
	        	ord++;
			}
			
	        if(turn == 1)
			{
				maxx[j-1] = ord;
				turn = 0;
				ord++;
				continue;				
			}
			else if(s->arr[maxx[j-1]].value < s->arr[ord].value)
				maxx[j-1] = ord;
				
			if(ord >= s->all-1)
	        {
	        	turn = 1;
				break;
			}				
		}	        
    }
    
	for(i=1; i<s->rownum; i++)
        for(j=1; j<s->colnum; j++)
            if(minn[i-1] == maxx[j-1]&&( s->arr[minn[i-1]].row == s->arr[maxx[j-1]].row )&&
				( s->arr[minn[i-1]].col == s->arr[maxx[j-1]].col ))///找到马鞍点
            {
                printf("array[%d][%d]=%d\n",s->arr[minn[i-1]].row,s->arr[minn[i-1]].col,s->arr[maxx[j-1]].value);
                have=true;
            }
    if(!have)
        printf("没有马鞍点\n");
}


void print_matrix(sparse_matrix a){
	
	int ord=0,zero = 0;
	
	for(int i = 1;i <= a.rownum;i++)
	{
		for(int j = 1;j <= a.colnum;j++)
		{
			if((i == a.arr[ord].row)&&
				(j == a.arr[ord].col))
				{
				printf("% 3d",a.arr[ord].value);
				ord++;
				}
			else
				printf("% 3d",zero);
			
		}
	printf("\n");
	}
	printf("\n");
}

int main()
{
	sparse_matrix a;
	printf("请输入矩阵行和列数：\n");
	scanf("%d %d",&a.rownum,&a.colnum);
	
	if(rand_array(&a)){
		printf("随机生成矩阵失败！\n");
		return 0;
	}
	print_matrix(a);
	MinMax(&a);
	
	return 0;
}

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