工作中遇到在shell中判断年份是否为闰年，写了一个shell方法
执行脚本并传入年份参数即可得到结果

#!bin/bash
function isLeapYear(){
	year=$1
	let "c1=$year % 4"
	let "c2=$year % 100"
	let "c3=$year % 400"
	if [ ! "$c1" -eq 0 ]
	then
		leap=0
	elif [ ! "$c2" -eq 0 ]
	then
		leap=1
	elif [ "$c3" -eq 0 ]
	then
		leap=1
	else
		leap=0
	fi
	echo $leap
}
a=$(isLeapYear $1)
echo "isLeapYear:"$a