Python中对矩阵的洗牌操作

【code】

import numpy as np

# 创建随机交换的索引
permutation = list(np.random.permutation(3)) # 创建矩阵X,Y
X = np.array([[0, 1, 2], [0, 1, 2], [0, 1, 2]])
Y = np.array([[0, 1, 2]]) # 交换顺序
shuffled_X = X[:, permutation]
shuffled_Y = Y[:, permutation] # 输出
print("permutation:")
print(permutation) print("X:")
print(X)
print("Y:")
print(Y) print("shuffled_X:")
print(shuffled_X)
print("shuffled_Y:")
print(shuffled_Y)

【result】

permutation:
[1, 2, 0]
X:
[[0 1 2]
[0 1 2]
[0 1 2]]

Y:
[[0 1 2]]

shuffled_X:
[[1 2 0]
[1 2 0]
[1 2 0]]

shuffled_Y:
[[1 2 0]]
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