题目链接:LibreOJ 10148 能量项链
题目大意:
题解:
一道典型的区间\(dp\)题。
状态转移方程:
#include <iostream>
using namespace std;
#define ll long long
#define N 1010
int a[N], n;
ll dp[N][N], ans;
int main() {
cin >> n;
for (int i = 1; i <= n; ++i) {
cin >> a[i];
a[n + i] = a[i];
}
for (int len = 1; len < n; ++len) {
for (int i = 1; i + len < 2 * n; ++i) {
int j = i + len;
dp[i][j] = 0;
for (int k = i; k < j; ++k) {
dp[i][j] = max(dp[i][j], dp[i][k] + dp[k + 1][j] + a[i] * a[k + 1] * a[j + 1]);
}
}
}
for (int i = 1; i <= n; ++i) {
ans = max(ans, dp[i][i + n - 1]);
}
cout << ans;
return 0;
}