我有三个简单的表格：用户,个人资料和观看的内容,其中包含用户的ID和观看的电影标题.

并且下面的脚本显示与所观察表中的不同用户匹配的值：

$id = $_SESSION['id'];
echo "my id: $id\n";

$movies = mysqli_query($connect, "SELECT w1.users_id AS user1, 
                                         w2.users_id AS user2, 
                                         COUNT(w2.watched) AS num_movies, 
                                         GROUP_CONCAT(w2.watched ORDER BY w2.watched) AS movies
                                  FROM watched w1
                                  JOIN watched w2 ON w2.watched = w1.watched AND w2.users_id != w1.users_id
                                  WHERE w1.users_id = $id
                                  GROUP BY user1, user2");
while ($row = $movies->fetch_assoc()) {
    echo "matched with id {$row['user2']} {$row['num_movies']} times on titles {$row['movies']}\n";
}

输出：

my id = `1`;
matched with id `2` 2 times on titles `movie2`, `movie1`;
matched with id `3` 1 times on titles `movie1`;

demo on fiddle

但是我还想显示用户的姓名,个人资料等.
像在此查询中一样：SELECT * FROM profile INNER JOIN users ON profile.users_id = users.id

如何合并第一个和第二个查询？

尝试过：

SELECT *, w2.watched, 
COUNT(w2.watched) AS num_movies, 
GROUP_CONCAT(w2.watched order by w2.watched) as movies

FROM profile AS p 
JOIN users AS u ON p.users_id = u.id 
LEFT JOIN watched AS w ON w.users_id = u.id and w.watched=w2.watched
     WHERE u.id != $id
     GROUP BY w.users_id

但它不起作用.

解决方法:

尝试这个

    SELECT w1.users_id AS user1,u.name as name, p.*, u.*, w2.users_id 
    AS user2, COUNT(w2.watched) AS num_movies, 
    GROUP_CONCAT(w2.watched ORDER BY w2.watched) AS movies 
    FROM watched w1 
    JOIN watched w2 ON w2.watched = w1.watched 
    AND w2.users_id != w1.users_id 
    JOIN users u ON u.id=w1.users_id 
    JOIN profile p ON p.users_id=w1.users_id 
    WHERE w1.users_id =1 GROUP BY user1, user2

输出