我突然发现【题目（11）】答案有一点问题，输出控制的那一段。所以我改了一下，还加了点小特效。（非常非常小的特效）
#include <iostream>
#include <string>
#include <sstream>
#include <iomanip>
#include "windows.h"
#include "stdio.h"
using namespace std;
string int2str(int aNum)
{
stringstream res;
res << aNum;
string s;
res >> s;
return s;
}
int char2int(char s)
{
stringstream res;
res << s;
int n;
res >> n;
return n;
}
int cifang16(int aNum, int time)//1 0
{
int sum = 1;
for(int i = 0; i < time; i++)
{
sum = sum * 16;
}
return sum * aNum;
}
int hex2dec(char hex, int time)
{
int num;
if(hex == 'A' || hex == 'a')
num = 10;
else if(hex == 'B' || hex == 'b')
num = 11;
else if(hex == 'C' || hex == 'c')
num = 12;
else if(hex == 'D' || hex == 'd')
num = 13;
else if(hex == 'E' || hex == 'e')
num = 14;
else if(hex == 'F' || hex == 'f')
num = 15;
else
num = char2int(hex);
num = cifang16(num, time);
return num;
}
int binLen;
string ShortDivide(int dec)
{
int everytime, yu;
string num = "";
while(dec != 0)
{
num += int2str(dec % 2);
dec = dec / 2;
}
binLen = num.size();
return num;
}
string Dec2Bin(int dec)
{
string lbin = ShortDivide(dec);
return lbin;
}
int main()
{
string hexNum;//十六进制数 △
printf("[Hex change to Bin]\n----------------\n");
printf("输入一个十六进制数:");
cin >> hexNum;//10
int hlen = hexNum.size();
int dec = 0;//十进制数 △
for(int i = 0; i < hlen; i++)
{
dec += hex2dec(hexNum[hlen - i - 1], i);
}
for(int i = 0; i < 3; i++){
cout << "……";
Sleep(1000);
}
cout << endl;
system("cls");
cout << "十进制数是 " << dec << endl;
//ShortDivide()函数
string bin = Dec2Bin(dec);//二进制数△
int k = binLen % 4;
cout << "二进制数是";
if(k == 0){
}
else
cout << setw(4 - k + 1) << setfill('0');
for(int i = binLen - 1; i >= 0; i--)
{
cout << bin[i];
}
cout << endl;
return 0;
}
其中Sleep（）是睡眠，也就是停顿一下，system（“cls”）是清屏，需要windows.h函数库
再点个赞，谢谢！