减法计数器 CountDownLatch
// 减法 计数器
// 每次有线程调用 countDown() 数量-1 假设计数器变为0 countDownLatch.await()就会被唤醒 继续执行
public class CountDownLatchDemo {
public static void main(String[] args) throws InterruptedException {
// 总数是6 必须要执行任务的时候 再使用
CountDownLatch countDownLatch = new CountDownLatch(6);
for (int i = 1; i <= 6; i++) {
new Thread(()->{
System.out.println(Thread.currentThread().getName()+" Go out");
countDownLatch.countDown();//-1
}, String.valueOf(i)).start();
}
countDownLatch.await(); // 等待计数器归零 然后再向下执行
System.out.println("关门");
}
}
加法计数器 CyclicBarrier
public class CyclicBarrierDemo {
public static void main(String[] args) {
CyclicBarrier cyclicBarrier = new CyclicBarrier(7, () -> {
System.out.println("召唤神龙");
});
for (int i = 1; i <= 7; i++) {
int temp = i;
new Thread(() -> {
System.out.println(Thread.currentThread().getName() + "==" + temp + "==");
try {
cyclicBarrier.await(); //等待
} catch (InterruptedException e) {
e.printStackTrace();
} catch (BrokenBarrierException e) {
e.printStackTrace();
}
}, String.valueOf(i)).start();
}
}
}
Semaphore: 信号位
public class SemaphoreDemo {
public static void main(String[] args) {
// 线程数量
Semaphore semaphore = new Semaphore(3);
for (int i = 1; i <= 6; i++) {
new Thread(() -> {
try {
semaphore.acquire(); // 得到
System.out.println(Thread.currentThread().getName() + "抢到车位");
TimeUnit.SECONDS.sleep(2);
System.out.println(Thread.currentThread().getName() + "离开车位");
} catch (InterruptedException e) {
e.printStackTrace();
} finally {
semaphore.release();//释放
}
}, String.valueOf(i)).start();
}
}
}
作用: 多个共享资源互斥的使用 并发限流 控制最大的线程数
JUC学习-4_JUC辅助类_CountDownLatch-CyclicBarrier-Semaphore