#include<iostream>

using namespace std;

struct point{

	int x;

	int y;

	int fun(point &p)		//在C++中，完全可以在struct中使用函数

	{

		p.x = 100;

		p.y = 200;

		return 0;

	}

	point(int x, int y): x(x) , y(y){ }		//等同于C++中的class

};

struct teacher{

	int age;

	char *name;

};

int main(void){

	point p(0,0);

	p.x = 1;

	p.y = 2;

	point p1= p;

	cout<<"p1.x="<<p1.x<<endl;

	cout<<"p1.y="<<p1.y<<endl;

	point *p3 = &p1;

	p3->x = 10;

	p3->y = 20;

	cout<<"p3->x="<<p3->x<<endl;

	cout<<"p3->y="<<p3->y<<endl;

	p3->fun(p1);

	cout<<"p3->x="<<p3->x<<endl;

	cout<<"p3->y="<<p3->y<<endl;

	point p4(1000,2000);

	cout<<"p4.x="<<p4.x<<endl;

	cout<<"p4.y="<<p4.y<<endl;

	cout<<"================struct在C中用法================"<<endl;

	cout<<"before define struct teacher,sizeof(teacher)="<<sizeof(teacher)<<endl;

	struct teacher t1;				//定义时比较繁琐，需要添加struct关键字,也可以使用typedef声明，此处就不需要加struct关键字。同样在C++中可以直接不加struct关键字

	cout<<"after define struct teacher,sizeof(teacher)="<<sizeof(teacher)<<endl;

	t1.age = 30;

	t1.name = "zhangsan";

	cout<<"t1.age="<<t1.age<<endl;

	cout<<"t1.name="<<t1.name<<endl;

	struct teacher *t2 = &t1;

	t2->age = 35;

	t2->name = "lisi";

	cout<<"t2->age="<<t2->age<<endl;

	cout<<"t2->name="<<t2->name<<endl;

	system("pause");

	return 0;

}