Mad scientist Mike is busy carrying out experiments in chemistry. Today he will attempt to join three atoms into one molecule.

A molecule consists of atoms, with some pairs of atoms connected by atomic bonds. Each atom has a valence number — the number of bonds the atom must form with other atoms. An atom can form one or multiple bonds with any other atom, but it cannot form a bond with itself. The number of bonds of an atom in the molecule must be equal to its valence number.

Mike knows valence numbers of the three atoms. Find a molecule that can be built from these atoms according to the stated rules, or determine that it is impossible.

The single line of the input contains three space-separated integers a, b and c (1 ≤ a, b, c ≤ 106) — the valence numbers of the given atoms.

If such a molecule can be built, print three space-separated integers — the number of bonds between the 1-st and the 2-nd, the 2-nd and the 3-rd, the 3-rd and the 1-st atoms, correspondingly. If there are multiple solutions, output any of them. If there is no solution, print "Impossible" (without the quotes).

 #include <iostream>

 #include <cstdio>

 using namespace std;

 int get13(int a, int b, int c)

 {

     int i;

     for(i = ; i <= a; ++i){

         if(c - i <= b && b - c + i == a - i && c - i >= ){

             return i;

         }

     }

     for(i = ; i <= a; ++i){

         if(b - i <= c && c - b + i == a - i && b - i >= ){

             return i + 10e7;

         }

     }

     return -;

 }

 int main()

 {

     int a, b, c;

     while(scanf("%d %d %d", &a, &b, &c) != EOF){

     int i = get13(a, b, c);

         if(i == -) {

             puts("Impossible");

         }

         else if(i < 10e7){

             printf("%d %d %d\n", a - i, b - a + i, i);

         }

         else{

             i -= 10e7;

             printf("%d %d %d\n", i, c - a + i, a - i);

         }

     }

     return ;

 }