Given an array of points
where points[i] = [xi, yi]
represents a point on the X-Y plane and an integer k
, return the k
closest points to the origin (0, 0)
.
The distance between two points on the X-Y plane is the Euclidean distance (i.e., √(x1 - x2)2 + (y1 - y2)2
).
You may return the answer in any order. The answer is guaranteed to be unique (except for the order that it is in).
Example 1:
Input: points = [[1,3],[-2,2]], k = 1 Output: [[-2,2]] Explanation: The distance between (1, 3) and the origin is sqrt(10). The distance between (-2, 2) and the origin is sqrt(8). Since sqrt(8) < sqrt(10), (-2, 2) is closer to the origin. We only want the closest k = 1 points from the origin, so the answer is just [[-2,2]].
Example 2:
Input: points = [[3,3],[5,-1],[-2,4]], k = 2 Output: [[3,3],[-2,4]] Explanation: The answer [[-2,4],[3,3]] would also be accepted.
Code:
1. Sort
class Solution: def kClosest(self, points: List[List[int]], k: int) -> List[List[int]]: return sorted(points, key=lambda x: x[0]* x[0] + x[1] * x[1])[:k]
2. Use heap
class Solution: def kClosest(self, points: List[List[int]], k: int) -> List[List[int]]: return heapq.nsmallest(k, points, key = lambda x: x[0]* x[0] + x[1] * x[1])