这个题我看了，都是推荐的神马双向广搜，难道这个深搜你们都木有发现？还是特意留个机会给我装逼？
Open the Lock
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 3014 Accepted Submission(s): 1323
Each time, you can add or minus 1 to any digit. When add 1 to '9', the digit will change to be '1' and when minus 1 to '1', the digit will change to be '9'. You can also exchange the digit with its neighbor. Each action will take one step.
Now your task is to use minimal steps to open the lock.
Note: The leftmost digit is not the neighbor of the rightmost digit.
Each test case begins with a four digit N, indicating the initial state of the password lock. Then followed a line with anotther four dight M, indicating the password which can open the lock. There is one blank line after each test case.
);
cout<<ss<<endl;
;
}
是不是水题？不是你就抽我，我擦！
最后发泄一下，妹的都说马化腾坑爹，这题目也坑啊，说什么每个case后面都空一行，就是输入最后一句啊，本人英语不行，所以先是全部输出ss后用两个endl，擦，说我PE，然后我控制，第二个endl我加个if(t)这就是控制只有两个输出之间有空格，妹的还是PE，好吧，我一怒之下就冲向我那个把这个鸟题过了的兄弟，调出代码，输入...输出...输入...输出...最后他说，空行是自己输入的......................我晕倒....