Problem Description

Conversion between the metric and English measurement systems is relatively simple. Often, it involves either multiplying or dividing by a constant. You must write a program that converts between the following units:

Input

The first line of input contains a single integer N, (1 ≤ N ≤ 1000) which is the number of datasets that follow.

Each dataset consists of a single line of input containing a floating point (double precision) number, a space and the unit specification for the measurement to be converted. The unit specification is one of kg, lb, l, or g referring to kilograms, pounds, liters and gallons respectively.

Output

For each dataset, you should generate one line of output with the following values: The dataset number as a decimal integer (start counting at one), a space, and the appropriately converted value rounded to 4 decimal places, a space and the unit specification for the converted value.

Sample Input

5

1 kg

2 l

7 lb

3.5 g

0 l

Sample Output

1 2.2046 lb

2 0.5284 g

3 3.1752 kg

4 13.2489 l

5 0.0000 g

题目很简单，就是给出了汇率，让你转换！！！

水题！

import java.util.Scanner;

public class Main{

    public static void main(String[] args) {

        Scanner sc = new Scanner(System.in);

        String[] str1 = {"kg","l","lb","g"};

        String[] str2 = {"lb","g","kg","l"};

        double[]  d = {2.2046,0.2642,0.4536,3.7854};

        int time = 1;

        int t = sc.nextInt();

        while(t-->0){

            int k=0;

            double n = sc.nextDouble();

            String s = sc.next();

            for(int i=0;i<str1.length;i++){

                if(s.equals(str1[i])){

                    k=i;

                    n = n*d[i];

                    break;

                }

            }

            System.out.printf("%d %.4f %s",time,n,str2[k] );

            System.out.println();

            time++;

        }

    }

}