# st='hello kitty {name} is {age}'
#
# print(st.count('l')) # 统计元素个数
# print(st.capitalize()) # 首字母大写
# print(st.center(50,'#')) # 居中
# print(st.endswith('tty3')) # 判断是否以某个内容结尾
# print(st.startswith('he')) # 判断是否以某个内容开头
# print(st.expandtabs(tabsize=20))
# print(st.find('t')) # 查找到第一个元素,并将索引值返回
# print(st.format(name='alex',age=37)) # 格式化输出的另一种方式 待定:?:{}
# print(st.format_map({'name':'alex','age':22}))
# print(st.index('t'))
# print('asd'.isalnum())
# print('12632178'.isdecimal())
# print('1269999.uuuu'.isnumeric())
# print('abc'.isidentifier())
# print('Abc'.islower())
# print('ABC'.isupper())
# print(' e'.isspace())
# print('My title'.istitle())
# print('My tLtle'.lower())
# print('My tLtle'.upper())
# print('My tLtle'.swapcase())
# print('My tLtle'.ljust(50,'*'))
# print('My tLtle'.rjust(50,'*'))
# print('\tMy tLtle\n'.strip())
# print('\tMy tLtle\n'.lstrip())
# print('\tMy tLtle\n'.rstrip())
# print('ok')
# print('My title title'.replace('itle','lesson',1))
# print('My title title'.rfind('t'))
# print('My title title'.split('i',1))
# print('My title title'.title()) #摘一些重要的字符串方法
#1 print(st.count('l'))
# print(st.center(50,'#')) # 居中
# print(st.startswith('he')) # 判断是否以某个内容开头
# print(st.find('t'))
# print(st.format(name='alex',age=37)) # 格式化输出的另一种方式 待定:?:{}
# print('My tLtle'.lower())
# print('My tLtle'.upper())
# print('\tMy tLtle\n'.strip())
# print('My title title'.replace('itle','lesson',1))
# print('My title title'.split('i',1))
# a=list()
# print(a) # dic={'name':'alex'} # dic1={}
# dic2=dict((('name','alex'),))
# print(dic2) # dic3=dict([['name','alex'],])
# print(dic3)
# ret2=dic1.setdefault('hobby','girl')
# print(dic1)
# print(ret2) # dic3={'age': 18, 'name': 'alex', 'hobby': 'girl'}
#
# print(dic3['name'])
#
# print(list(dic3.keys()))
# print(list(dic3.values()))
# print(list(dic3.items())) # li=[1,2,34,4]
# li[2]=5
# dic3={'age': 18, 'name': 'alex', 'hobby': 'girl'}
# dic3['age']=55
# print(dic3) # dic4={'age': 18, 'name': 'alex', 'hobby': 'girl'}
# # dic5={'1':'111','2':'222'}
# dic5={'1':'111','name':'222'}
#
# dic4.update(dic5)
# print(dic4)
# print(dic5)
# dic1={'name':'alex'}
# dic1['age']=18
# print(dic1)
# dic5 = {'name': 'alex', 'age': 18, 'class': 1} # dic5.clear() # 清空字典
# print(dic5)
# del dic5['name'] #删除字典中指定键值对
# print(dic5) # print(dic5.pop('age')) #删除字典中指定键值对,并返回该键值对的值
# ret=dic5.pop('age')
# print(ret)
# print(dic5) # a = dic5.popitem() #随机删除某组键值对,并以元组方式返回值
# print(a, dic5) # del dic5 #删除整个字典
# print(dic5)