把常见的日期格式如：YYYY-MM-DD 转换成一种更易读的格式。
易读格式应该是用月份名称代替月份数字，用序数词代替数字来表示天 (1st 代替 1)。
包含当前年份和相同月份的时候，makeFriendlyDates(["2017-01-02", "2017-01-05"]) 应该返回 ["January 2nd","5th"]。
不包含当前年份，makeFriendlyDates(["2003-08-15", "2009-09-21"]) 应该返回 ["August 15th, 2003", "September 21st, 2009"]。
请考虑清楚所有可能出现的情况，包括传入的日期区间是否合理。对于不合理的日期区间，直接返回 undefined 即可。
思路：
就是几个条件判断一下就行了。写的有点繁琐，有更简便的请留言。
let makeFriendlyDates = arr => {
const months = {"01" : "January","02" : "February","03" : "March", "04" : "April","05" : "May", "06" : "June", "07" : "July","08" : "August", "09" : "September","10" : "October", "11" : "November","12" : "December" };
let date1 = arr[0].split("-");
let date2 = arr[1].split("-");
let date = new Date();
let dateChange = day => {
if(day[0] === "0"){
day = day.substr(1);
if(day === "1") return day + "st"; //01->1st
if(day === "2") return day + "nd"; //02->2nd
if(day === "3") return day + "rd"; //03->3rd
else return day + "th";
}
else{
if(day.substr(1,1) === "1" && day.substr(0,1) === "2") return day + "st"; //21->21st
if(day.substr(1,1) === "1" && day.substr(0,1) === "3") return day + "st"; //31->31st
if(day.substr(1,1) === "2" && day.substr(0,1) === "2") return day + "nd"; //22->22nd
if(day.substr(1,1) === "3" && day.substr(0,1) === "2") return day + "rd"; //23->23rd
else return day + "th";
}
};
let sameYear = (d1, d2) => {
if(d2[0] - d1[0] > 1) return false;
else{
if(d1[0] === d2[0]) return true;
else{ //判断相减为1的时候
if(d2[1] > d1[1]) return false;
if(d2[1] < d1[1]) return true; //判断在一年以内返回true
else return d2[2] < d1[2] ? true : false; //判断是否在一年以内
}
}
};
if (sameYear(date1, date2)) {
if(date1[0] === date2[0]){
if(date1[1] === date2[1]){ //月份相同
if(date1[2] === date2[2]){ //日期相同
let dateArr = [];
dateArr.push(months[date1[1]] + " " + dateChange(date1[2]) + ", " + date1[0]);
return dateArr;
}
else{
let dateArr = [];
dateArr.push(months[date1[1]] + " " + dateChange(date1[2]));
dateArr.push(dateChange(date2[2]));
return dateArr;
}
}
else{ //月份不同
let dateArr = [];
dateArr.push(months[date1[1]] + " " + dateChange(date1[2]));
dateArr.push(months[date2[1]] + " " + dateChange(date2[2]));
return dateArr;
}
}
if(date1[0] == date.getFullYear() - 1){ //开始年份为当前年份
let dateArr = [];
dateArr.push(months[date1[1]] + " " + dateChange(date1[2]));
dateArr.push(months[date2[1]] + " " + dateChange(date2[2]));
return dateArr;
}
else{
let dateArr = [];
dateArr.push(months[date1[1]] + " " + dateChange(date1[2]) + ", " + date1[0]);
dateArr.push(months[date2[1]] + " " + dateChange(date2[2]));
return dateArr;
}
}
if (date2[0] > date1[0]){ //不同年且d2比d1大时
let dateArr = [];
dateArr.push(months[date1[1]] + " " + dateChange(date1[2]) + ", " + date1[0]);
dateArr.push(months[date2[1]] + " " + dateChange(date2[2]) + ", " + date2[0]);
return dateArr;
}
}
makeFriendlyDates(["2017-02-05", "2017-03-03"]);
如果有不明白的地方请留言，如果有更好更简便更优化的方法请留言，谢谢。
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