test2

n = n % m;
		Vector v = new Vector();
		for (;;) {
			int a=0;
			v.add(n);
			n *= 10;
			n = n % m;
			if (n == 0)
				return 0;
			if (v.indexOf(n) > 0) {
   		       return v.size()-v.indexOf(n); //减去n的主要目的是有些循环节为0.36666循环节长度此时为1
   		   // [11, 6, 8, 2, 7, 5, 11] //-v.indexOf(n)需要减去11
			} // _________________________________;填空
		}

test2test2test2test2

test2

# test2test2

`n = n % m;
Vector v = new Vector();
for (;