http://acm.hdu.edu.cn/showproblem.php?pid=2051
Problem Description
Give you a number on base ten,you should output it on base two.(0 < n < 1000)
Input
For each case there is a postive number n on base ten, end of file.
Output
For each case output a number on base two.
Sample Input
1
2
3
Sample Output
1
10
11
代码：
#include <bits/stdc++.h>
using namespace std;
char num[3]= {'0','1'};
char ans[1111];
int main()
{
int n;
while(~scanf("%d",&n))
{
int numm=0;
do
{
ans[numm++]=num[n%2];
n/=2;
}
while(n!=0);
for(int i=numm-1;i>=0;i--)
{
if(i!=0)
printf("%c",ans[i]);
else
printf("%c\n",ans[i]);
}
}
return 0;
}