题目是这样的

求一个字符串中连续字母的个数

比如I have a book. : 1

I have a dog. : 0

I haavee aa dogg : 4

#include <windows.h>

#include <iostream>

using namespace std;

void GetDupStringCount( const char* pStr, int &iOut )

{

	if( !pStr )

		return;

	int iLen = strlen( pStr );

	if( !iLen )

		return;

	char cValue = *pStr;

	int iNumCount = 0;//重复个数

	iOut = 0;//设置为0

	int iIndex = 0;//当前索引

	while( iLen-- )

	{

		if( !( ( cValue >= 'a' && cValue <= 'z' ) || ( cValue >= 'A' && cValue <= 'Z' ) ) )

		{

			cValue = *( pStr + ++iIndex );

			iNumCount = 0;

			continue;

		}

		if( cValue == *( pStr + iIndex ) )

		{

			iNumCount++;

		}

		else

		{

			cValue = *( pStr + iIndex );

			if( iNumCount > 1 )

			{

				iOut++;

				iNumCount = 0;

				--iIndex;

			}

		}

		iIndex++;

	}

}

int main( int argc, char* argv[] )

{

	char szStr[] = " I haveee  a book!   ";

	int iOut = -1;

	GetDupStringCount( szStr, iOut );

	cout << iOut << endl;

	return 0;

}