简单使用shell 自动打包,发布项目 脚本

(1)打包,发布脚本

deploy.sh

packagepath=/home/admin/testProject/project

application=testProject

mkdir -p $packagepath

cd $packagepath || exit

[ -d $packagepath/$application ] || git clone git@git.hello.so:powergreen/${application}.git

[ -d $packagepath/$application/.git ] || ( rm -rf $packagepath/$application/ && git clone git@git.hello.so:powergreen/${application}.git )
cd $packagepath/$application || exit
git checkout dev
git pull # generate a folder and a file which named xx.war, such as lhc lhc.war # under the folder $application-web/target # we just need the .war file mvn clean package -Dmaven.test.skip -U -Pdev -e cd $packagepath/$application/testProject-web/target/ java -Xdebug -Xrunjdwp:server=y,transport=dt_socket,address=9091,suspend=n -jar testProject.jar &

关闭进程脚本

stop.sh(要输入进程的名称

#! /bin/bash

if [ $# -lt 1 ]
then
echo "缺少参数:procedure_name"
exit 1
fi
PROCESS=`ps -ef|grep $1|grep -v grep|grep -v PPID|awk '{ print $2}'`
for i in $PROCESS
do
echo "Kill the $1 process [ $i ]"
kill -9 $i
done

bulid.sh 执行bulid.sh [start|stop] 开始打包发布脚本

命令 :  ./bulid.sh  start 发布项目

./bulid.sh  stop 停止项目

#! /bin/bash

sOn=$1
name=testProject
echo "执行操作:$sOn" if test $sOn = "start";
then
echo '停止${name}'
source /home/admin/testProject/scripts/stop.sh ${name}
echo '开始启动${name}'
source /home/admin/testProject/scripts/deploy.sh
exit 1
else
if test $sOn = "stop";
then
echo '停止${name}'
source /home/admin/testProject/scripts/stop.sh ${name}
exit 1
else
echo '参数错误'
exit 1
fi
fi
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