11jqGrid - 配置json

IE8,FF3以及Chrome 3已经支持JSON,配置:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">

<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">

	<head>

		<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />

		<title>My First Grid</title>

		<link rel="stylesheet" type="text/css" media="screen" href="css/ui-lightness/jquery-ui-1.7.1.custom.css" />

		<link rel="stylesheet" type="text/css" media="screen" href="css/ui.jqgrid.css" />

		<script src="js/jquery-1.3.2.min.js" type="text/javascript"></script>

		<script src="js/i18n/grid.locale-en.js" type="text/javascript"></script>

		<script type="text/javascript">
			jQuery.jgrid.useJSON = true;
		</script>

		<script src="js/jquery.jqGrid.min.js" type="text/javascript"></script>

	</head>

	<body>

		...

	</body>

</html>

这段代码要放到语言包之后jqGrid.js文件之前。
如果浏览器不支持JSON,那么我们只能用eval函数解析json。
除了jqGrid本身提供对json的类库外,我们可以使用JSON.parse来处理JSON,配置如下:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">

<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">

	<head>

		<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />

		<title>My First Grid</title>

		<link rel="stylesheet" type="text/css" media="screen" href="css/ui-lightness/jquery-ui-1.7.1.custom.css" />

		<link rel="stylesheet" type="text/css" media="screen" href="css/ui.jqgrid.css" />

		<script src="js/json2.js" type="text/javascript"></script>

		<script src="js/jquery-1.3.2.min.js" type="text/javascript"></script>

		<script src="js/i18n/grid.locale-en.js" type="text/javascript"></script>

		<script src="js/jquery.jqGrid.min.js" type="text/javascript"></script>

		<script type="text/javascript">
			jQuery.extend(jQuery.jgrid, {

				parse: function(jsstring) {

					return JSON.parse(jsstring);

				}

			});
		</script>

	</head>

	<body>

		...

	</body>

</html>

 

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