SQL-学习使用FOR XML PATH

2024-01-10 10:46:22

前言:本人SQL技术很烂,然后工作时间也不久,许多东西都还在学习中,说的不好的地方尽请谅解.

首先跟大家说一下我今天遇到的问题吧.

查出的数据有三列,第一列存放的是32位的GUID,Res_Name存放的是一个物资类型.Res_Data存放的是部门的GUID.我现在需要得到的数据是这样的.

首先大家可以看到.第一张图的Res_Data中有多个部门的GUID,中间用逗号隔开的.

我当时想到的愚蠢的办法就是

 1 @MaterialTypeName nvarchar(200),
 2 @CentralizedName nvarchar(200),
 3 @start int,
 4 @limit int,
 5 @totalCount int output 
 6 AS
 7 BEGIN
 8     SET NOCOUNT ON;
 9     select 
10         ROW_NUMBER() over (order by res_id asc) as RowNumber,
11         * 
12     into #List 
13     from 
14         UBIPlatform..T_RESOURCE 
15     WHERE Res_Parent_Code=‘741cdd2bef2e479f8c5dd35cf6e8bf2a‘
16      
17         
18     declare @i int,@count int;
19     declare @Centralized nvarchar(200);
20     declare @List1 table(id int, ResId nvarchar(50),ResName nvarchar(50),ResData nvarchar(50));
21     select @count=COUNT(*) from UBIPlatform..T_RESOURCE WHERE Res_Parent_Code=‘741cdd2bef2e479f8c5dd35cf6e8bf2a‘ 
22     set @i=1
23     while @i<=@count
24     begin
25         if @i in (select RowNumber from #List)
26         begin
27             set @Centralized=‘‘;
28             select 
29                 @Centralized=@Centralized+‘,‘+LTRIM(Res_Name) 
30             from UBIPlatform.dbo.FN_GETMultiValTable(
31                 (select 
32                     Res_Data 
33                 from 
34                     UBIPlatform..T_RESOURCE 
35                 where 
36                     Res_Id=(select Res_Id from #List where RowNumber=@i))) ge
37             inner join UBIPlatform..T_RESOURCE r on r.Res_Id=ge.nvalue
38             
39             if @Centralized!=‘‘
40             begin
41                 insert into 
42                     @List1 
43                 select 
44                     @i,
45                     Res_Id,
46                     Res_Name,
47                     (RIGHT(@Centralized,LEN(@Centralized)-1)) 
48                 from 
49                     UBIPlatform..T_RESOURCE 
50                 where Res_Id=(select Res_Id from #List where RowNumber=@i)
51             end
52             else
53             begin
54                 insert into 
55                     @List1 
56                 select 
57                     @i,
58                     Res_Id,
59                     Res_Name,
60                     @Centralized
61                 from 
62                     UBIPlatform..T_RESOURCE 
63                 where Res_Id=(select Res_Id from #List where RowNumber=@i)
64             end    
65         end
66         set @i=@i+1
67     end
68     
69     select ROW_NUMBER() over (order by id asc) as RowNumber,* into #List2 from @List1 where 
70     (@MaterialTypeName is null or @MaterialTypeName = ‘‘ or ResName  like ‘%‘+@MaterialTypeName+‘%‘)
71     and (@CentralizedName is null or @CentralizedName = ‘‘ or ResData  like ‘%‘+@CentralizedName+‘%‘)
72     
73     select top(@limit) * from #List2 where RowNumber > @start order by RowNumber asc
74     select @totalCount =COUNT(1) from @List1
75 END

View Code

这个是我开始写出来的一个.烂到不行.虽然是解决了我的需求.但是显而易见这种办法是不可取的.后来请教同事,跟我介绍了FOR XML PATH,我查阅了一下就是将查询结果集以XML形式展现.

select Res_Id,Res_Name,Res_Data from UBIPlatform..T_RESOURCE where Res_Parent_Code=‘741cdd2bef2e479f8c5dd35cf6e8bf2a‘ FOR XML PATH

结果:

 1 <row>
 2   <Res_Id>239dbe35bd8446afb262f62712d8eb1b</Res_Id>
 3   <Res_Name>修理费-设备备件</Res_Name>
 4   <Res_Data>4BD2D7C9D91546B09BA4438EE583F682</Res_Data>
 5 </row>
 6 <row>
 7   <Res_Id>4d35c89868854d649963410a126b4c30</Res_Id>
 8   <Res_Name>低值易耗-计量器具</Res_Name>
 9   <Res_Data>4ADEEC453DE04910B0136593CBB4187C</Res_Data>
10 </row>
11 <row>
12   <Res_Id>4e74469a37894ea8a7ddd5e356433119</Res_Id>
13   <Res_Name>物料消耗-计算机耗材</Res_Name>
14   <Res_Data>4BD2D7C9D91546B09BA4438EE583F682,9C87FFAFD8D24B5BBEA3BF1221DD507B</Res_Data>
15 </row>
16 <row>
17   <Res_Id>608f30860c16430aa8b13f98df0ca9f3</Res_Id>
18   <Res_Name>物料消耗-水票</Res_Name>
19   <Res_Data></Res_Data>
20 </row>
21 <row>
22   <Res_Id>87a4cefa112241c1b648454e7b3682d9</Res_Id>
23   <Res_Name>低值易耗-工具及其他</Res_Name>
24   <Res_Data></Res_Data>
25 </row>
26 <row>
27   <Res_Id>c2908fe510dd476aa878622dd9d07c83</Res_Id>
28   <Res_Name>物料消耗-杂品</Res_Name>
29   <Res_Data></Res_Data>
30 </row>
31 <row>
32   <Res_Id>c9014727c9804c6e9df4cc1bc1487a84</Res_Id>
33   <Res_Name>劳动保护费-劳保用品</Res_Name>
34   <Res_Data>D5566FDCDBB448FAB4A48D20A2492626</Res_Data>
35 </row>
36 <row>
37   <Res_Id>d3397fdcb454440f88c9c4f9432b3f40</Res_Id>
38   <Res_Name>低值易耗-办公设施</Res_Name>
39   <Res_Data>9C87FFAFD8D24B5BBEA3BF1221DD507B</Res_Data>
40 </row>
41 <row>
42   <Res_Id>d8222bcaeaba460db945324cb0a93a23</Res_Id>
43   <Res_Name>修理费-计算机备件</Res_Name>
44   <Res_Data>4BD2D7C9D91546B09BA4438EE583F682</Res_Data>
45 </row>

View Code

那么，如何改变XML行节点的名称呢？代码如下：

select Res_Id,Res_Name,Res_Data from UBIPlatform..T_RESOURCE where Res_Parent_Code=‘741cdd2bef2e479f8c5dd35cf6e8bf2a‘ FOR XML PATH(‘RESOURCE‘)

原来的行节点<row> 变成了我们在PATH后面括号()中，自定义的名称<RESOURCE>,结果如下：

<RESOURCE>
  <Res_Id>239dbe35bd8446afb262f62712d8eb1b</Res_Id>
  <Res_Name>修理费-设备备件</Res_Name>
  <Res_Data>4BD2D7C9D91546B09BA4438EE583F682</Res_Data>
</RESOURCE>
<RESOURCE>
  <Res_Id>4d35c89868854d649963410a126b4c30</Res_Id>
  <Res_Name>低值易耗-计量器具</Res_Name>
  <Res_Data>4ADEEC453DE04910B0136593CBB4187C</Res_Data>
</RESOURCE>
<RESOURCE>
  <Res_Id>4e74469a37894ea8a7ddd5e356433119</Res_Id>
  <Res_Name>物料消耗-计算机耗材</Res_Name>
  <Res_Data>4BD2D7C9D91546B09BA4438EE583F682,9C87FFAFD8D24B5BBEA3BF1221DD507B</Res_Data>
</RESOURCE>
<RESOURCE>
  <Res_Id>608f30860c16430aa8b13f98df0ca9f3</Res_Id>
  <Res_Name>物料消耗-水票</Res_Name>
  <Res_Data></Res_Data>
</RESOURCE>
<RESOURCE>
  <Res_Id>87a4cefa112241c1b648454e7b3682d9</Res_Id>
  <Res_Name>低值易耗-工具及其他</Res_Name>
  <Res_Data></Res_Data>
</RESOURCE>
<RESOURCE>
  <Res_Id>c2908fe510dd476aa878622dd9d07c83</Res_Id>
  <Res_Name>物料消耗-杂品</Res_Name>
  <Res_Data></Res_Data>
</RESOURCE>
<RESOURCE>
  <Res_Id>c9014727c9804c6e9df4cc1bc1487a84</Res_Id>
  <Res_Name>劳动保护费-劳保用品</Res_Name>
  <Res_Data>D5566FDCDBB448FAB4A48D20A2492626</Res_Data>
</RESOURCE>
<RESOURCE>
  <Res_Id>d3397fdcb454440f88c9c4f9432b3f40</Res_Id>
  <Res_Name>低值易耗-办公设施</Res_Name>
  <Res_Data>9C87FFAFD8D24B5BBEA3BF1221DD507B</Res_Data>
</RESOURCE>
<RESOURCE>
  <Res_Id>d8222bcaeaba460db945324cb0a93a23</Res_Id>
  <Res_Name>修理费-计算机备件</Res_Name>
  <Res_Data>4BD2D7C9D91546B09BA4438EE583F682</Res_Data>
</RESOURCE>

View Code

OK,接下来我就用这个FOR XML PATH用在我的问题上,

@MaterialTypeName nvarchar(200),
@CentralizedName nvarchar(200),
@start int,
@limit int,
@totalCount int output 
AS
BEGIN
    SET NOCOUNT ON;    
    select 
        t_r.Res_Id as ResId,
        t_r.Res_Name as ResName,
        STUFF((select ‘,‘+t_r1.Res_Name               
    from UBIPlatform.dbo.T_RESOURCE t_r1 where t_r1.Res_Id in 
        (select nvalue from UBIPlatform.dbo.FN_GETMultiValTable(t_r.Res_Data))            
        for xml path(‘‘)),1,1,‘‘) as ResData 
    into 
        #List1  
    from 
        UBIPlatform..T_RESOURCE t_r 
    where Res_Parent_Code=‘741cdd2bef2e479f8c5dd35cf6e8bf2a‘
    
    select 
        ROW_NUMBER() over (order by ResId asc) as RowNumber,
        * into #List2 from #List1
    where (@MaterialTypeName is null or @MaterialTypeName = ‘‘ or ResName  like ‘%‘+@MaterialTypeName+‘%‘)
    and (@CentralizedName is null or @CentralizedName = ‘‘ or ResData  like ‘%‘+@CentralizedName+‘%‘)
    
    select top(@limit) * from #List2 where RowNumber > @start order by RowNumber asc
    select @totalCount =COUNT(1) from #List2
END

就这样,才几行的SQL就把我的问题解决了.

SQL-学习使用FOR XML PATH

码农公寓

相关文章