问题描述:
无线电台的RS制信号报告是由三两个部分组成的:
R(Readability) 信号可辨度即清晰度.
S(Strength) 信号强度即大小.
其中R位于报告第一位,共分5级,用1—5数字表示.
1---Unreadable
2---Barely readable, occasional words distinguishable
3---Readable with considerable difficulty
4---Readable with practically no difficulty
5---Perfectly readable
报告第二位是S,共分九个级别,用1—9中的一位数字表示
1---Faint signals, barely perceptible
2---Very weak signals
3---Weak signals
4---Fair signals
5---Fairly good signals
6---Good signals
7---Moderately strong signals
8---Strong signals
9---Extremely strong signals
现在,你的程序要读入一个信号报告的数字,然后输出对应的含义。如读到59,则输出:
Extremely strong signals, perfectly readable.
输入格式:
一个整数,信号报告。整数的十位部分表示可辨度,个位部分表示强度。输入的整数范围是[11,59]内有效的数字,这个范围外的数字不可能出现在测试数据中。
输出格式:
一句话,表示这个信号报告的意义。按照题目中的文字,先输出表示强度的文字,跟上逗号和空格,然后是表示可辨度的文字,跟上句号。注意可辨度的句子的第一个字母是小写的。注意这里的标点符号都是英文的。
输入样例:
33
输出样例:
Weak signals, readable with considerable difficulty.
时间限制:500ms内存限制:32000kb 问题分析: 对switch循环的简单运用 代码实现:import java.util.Scanner; public class 信号报告 { public static void main(String[] args) { Scanner in=new Scanner(System.in); int i; int first; int second; i=in.nextInt(); second=i/10;//十位数 first=i%10;//个位数 if(i>=11&&i<=59) { switch(first) //个位数值决定第一句话 { case 1: System.out.print("Faint signals, barely perceptible,"); break; case 2: System.out.print("Very weak signals,"); break; case 3: System.out.print("Weak signals,"); break; case 4: System.out.print("Fair signals,"); break; case 5: System.out.print("Fairly good signals,"); break; case 6: System.out.print("Good signals,"); break; case 7: System.out.print("Moderately strong signals,"); break; case 8: System.out.print("Strong signals,"); break; case 9: System.out.print("Extremely strong signals,"); break; } switch(second) //十位数值决定第二句话 { case 1: System.out.print("Unreadable."); break; case 2: System.out.print("Barely readable, occasional words distinguishable."); break; case 3: System.out.print("Readable with considerable difficulty."); break; case 4: System.out.print("Readable with practically no difficulty."); break; case 5: System.out.print("Perfectly readable."); break; } } else { System.out.println("输入数字错误!"); } in.close(); } }