滴水逆向-结构体

滴水逆向-结构体

 

 滴水逆向-结构体

 

 滴水逆向-结构体

 

滴水逆向-结构体

 

滴水逆向-结构体

 

 相关测试代码

结构体的定义与使用
        
    struct st //struct是一个关键字 st是用户自己定义的一个名字    
    {    
              //可以定义多种类型
        int a;
        char b;
        short c;
    };    
        
    结构体的使用    
        
    void Function(person p)    
    {    
        st s;
        s.a = 10;
        s.b = 20;
        s.c = 30;
    }    
        
练习测试

#include "stdafx.h"        


struct st 
{
    char a;
    short b;
    int c;
};

struct st1 
{
    int a;
    int b;
};

struct st2 
{
    short a;
    short b;
};

struct st3 
{
    char a;
    char b;
};

struct st4 
{
    char a4;
    short b4;
    int c4;
    int arr4[10];
    st1 d4;
};


void fun(){

    st cntf;
    st1 cntf1;
    st2 cntf2;
    st3 cntf3;
    st4 cntf4;

    cntf.a = 10;
    cntf.b = 12;
    cntf.c = 14;

    cntf1.a = 8;
    cntf1.b = 10;

    cntf2.a = 13;
    cntf2.b = 15;

    cntf3.a = 1;
    cntf3.b = 2;

    cntf4.a4 = 6;
    cntf4.arr4[2] = 76;
    cntf4.b4 = 5;
    cntf4.c4 = 88;
    cntf4.d4.a = 90;
    
    printf("%d %d %d \n",cntf.a,cntf.b,cntf.c);
}


int main(int argc, char* argv[])
{    
    fun();
    return 0;
}            
    
        
说明:结构体在定义的时候,除了自身以外,可以使用任何类型。    
        
        
    struct st1    
    {    
        int a;
        int b;
    };    
    struct st2    
    {    
        char a;
        short b;
        int arr[10];
        st1 s;
    };    
    void Funtion()    
    {    
        st2 s2;
        
        s2.a = 'A';
        s2.b = 12;
        s2.arr[0] = 1;
        s2.arr[1] = 2;
        s2.arr[3] = 3;
        s2.s.a = 100;
        s2.s.b = 200;
        
        printf("%d\n",s2.s.a);
    }    


结构体作为参数的时候,下面的练习测试代码的结果可以知道实际结构体作为参数底层是在左内存的复制,非常消耗内存
    
练习测试代码

#include "stdafx.h"        


struct st 
{
    char a;
    short b;
    int c;
};

struct st1 
{
    int a;
    int b;
};

struct st2 
{
    short a;
    short b;
};

struct st3 
{
    char a;
    char b;
};

struct st4 
{
    char a4;
    short b4;
    int c4;
    int arr4[10];
    st1 d4;
};


void fun(st4 ct4){

    st cntf;
    st1 cntf1;
    st2 cntf2;
    st3 cntf3;
    st4 cntf4;

    cntf.a = 10;
    cntf.b = 12;
    cntf.c = 14;

    cntf1.a = 8;
    cntf1.b = 10;

    cntf2.a = 13;
    cntf2.b = 15;

    cntf3.a = 1;
    cntf3.b = 2;

    cntf4.a4 = 6;
    cntf4.arr4[2] = 76;
    cntf4.b4 = 5;
    cntf4.c4 = 88;
    cntf4.d4.a = 90;
    
    printf("%d %d %d \n",cntf.a,cntf.b,cntf.c);
}


int main(int argc, char* argv[])
{    
    st4 ct4;
    ct4.a4 = 88;
    ct4.arr4[6] = 98;
    ct4.b4 = 65;
    ct4.c4 = 76;
    ct4.d4.a = 90;
    fun(ct4);
    return 0;
}            
    
    
反汇编代码

74:   {
0040B8E0   push        ebp
0040B8E1   mov         ebp,esp
0040B8E3   sub         esp,78h
0040B8E6   push        ebx
0040B8E7   push        esi
0040B8E8   push        edi
0040B8E9   lea         edi,[ebp-78h]
0040B8EC   mov         ecx,1Eh
0040B8F1   mov         eax,0CCCCCCCCh
0040B8F6   rep stos    dword ptr [edi]
75:       st4 ct4;
76:       ct4.a4 = 88;
0040B8F8   mov         byte ptr [ebp-38h],58h
77:       ct4.arr4[6] = 98;
0040B8FC   mov         dword ptr [ebp-18h],62h
78:       ct4.b4 = 65;
0040B903   mov         word ptr [ebp-36h],offset main+27h (0040b907)
79:       ct4.c4 = 76;
0040B909   mov         dword ptr [ebp-34h],4Ch
80:       ct4.d4.a = 90;
0040B910   mov         dword ptr [ebp-8],5Ah
81:       fun(ct4);
0040B917   sub         esp,38h
0040B91A   mov         ecx,0Eh
0040B91F   lea         esi,[ebp-38h]
0040B922   mov         edi,esp
0040B924   rep movs    dword ptr [edi],dword ptr [esi]
0040B926   call        @ILT+115(fun) (00401078)
0040B92B   add         esp,38h



结构体作为返回值

    struct st    
    {    
        char a;
        short b;
        int c;
        int d;
        int e;
        
    };    
    st Function()    
    {    
        st s;
        s.a = 1;
        s.b = 2;
        s.c = 3;
        s.d = 4;
        s.e = 5;
        
        return s;
    };    
    int main(int argc, char* argv[])    
    {    
        st s = Function();
        
        
        return 0;
    }    
    
练习测试代码

#include "stdafx.h"        


struct st 
{
    char a;
    short b;
    int c;
};

struct st1 
{
    int a;
    int b;
};

struct st2 
{
    short a;
    short b;
};

struct st3 
{
    char a;
    char b;
};

struct st4 
{
    char a4;
    short b4;
    int c4;
    int arr4[10];
    st1 d4;
};


st4 fun(){

    st cntf;
    st1 cntf1;
    st2 cntf2;
    st3 cntf3;
    st4 cntf4;

    cntf.a = 10;
    cntf.b = 12;
    cntf.c = 14;

    cntf1.a = 8;
    cntf1.b = 10;

    cntf2.a = 13;
    cntf2.b = 15;

    cntf3.a = 1;
    cntf3.b = 2;

    cntf4.a4 = 6;
    cntf4.arr4[2] = 76;
    cntf4.b4 = 5;
    cntf4.c4 = 88;
    cntf4.d4.a = 90;
    
    //printf("%d %d %d \n",cntf.a,cntf.b,cntf.c);
    return cntf4;
}


int main(int argc, char* argv[])
{    
    st4 cntf4 = fun();
    return 0;
}    

对应反汇编代码

63:       cntf4.a4 = 6;
0040B9D1   mov         byte ptr [ebp-50h],6
64:       cntf4.arr4[2] = 76;
0040B9D5   mov         dword ptr [ebp-40h],4Ch
65:       cntf4.b4 = 5;
0040B9DC   mov         word ptr [ebp-4Eh],offset fun+60h (0040b9e0)
66:       cntf4.c4 = 88;
0040B9E2   mov         dword ptr [ebp-4Ch],58h
67:       cntf4.d4.a = 90;
0040B9E9   mov         dword ptr [ebp-20h],5Ah
68:
69:       //printf("%d %d %d \n",cntf.a,cntf.b,cntf.c);
70:       return cntf4;
0040B9F0   mov         ecx,0Eh
0040B9F5   lea         esi,[ebp-50h]
0040B9F8   mov         edi,dword ptr [ebp+8]
0040B9FB   rep movs    dword ptr [edi],dword ptr [esi]
0040B9FD   mov         eax,dword ptr [ebp+8]
71:   }




sizeof的使用

    char a = 10;            
    short b = 20;            
    int c = 30;            
                
    char arr1[10] = {0};            
    short arr2[10] = {0};            
    int arr3[10] = {0};            
                
    printf("%d\n",sizeof(a));            
    printf("%d\n",sizeof(b));            
    printf("%d\n",sizeof(c));            
    printf("%d\n",sizeof(arr1));            
    printf("%d\n",sizeof(arr2));            
    printf("%d\n",sizeof(arr3));            
                
                
                
    struct st1            
    {            
        char a;        
        short b;        
        int c;        
    };            
    struct st2            
    {            
        char a;        
        int c;        
        short b;        
    };            
    int main(int argc, char* argv[])            
    {            
        st1 s1;        
        st2 s2;        
                
        printf("%d\n",sizeof(s1));        
        printf("%d\n",sizeof(s2));        
                
        return 0;        
    }            
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