遇到这样的要求：无论在哪个应用程序view controller，摇动手机，我们可以启动的方法。

你可以认为这个想法是使用包装的苹果“MotionEvent”。但是，假如简单地把代码添加到view controller于，所以只存在view controller示在前端时，摇动手机才会出发方法。

- (BOOL)canBecomeFirstResponder {//默认是NO，所以得重写此方法，设成YES

     return YES;

}

然后实现下列方法://非常像TouchEvent事件

- (void)motionBegan:(UIEventSubtype)motion withEvent:(UIEvent *)event

{

}

- (void)motionEnded:(UIEventSubtype)motion withEvent:(UIEvent *)event

{

    NSLog(@"shake");

}

- (void)motionCancelled:(UIEventSubtype)motion withEvent:(UIEvent *)event

{

}

解决方法：用Category扩展UIWindow。代码例如以下：

UIWindow+.h

#import <UIKit/UIKit.h>

#define UIEventSubtypeMotionShakeNotification @"UIEventSubtypeMotionShakeNotification"

@interface UIWindow (Motion)

// @override

- (BOOL)canBecomeFirstResponder;

- (void)motionEnded:(UIEventSubtype)motion withEvent:(UIEvent *)event;

@end

UIWindow+.m

#import "UIWindow+.h"

@implementation UIWindow (Motion)

- (BOOL)canBecomeFirstResponder {//默认是NO，所以得重写此方法。设成YES

     return YES;

}

然后实现下列方法://非常像TouchEvent事件

- (void)motionBegan:(UIEventSubtype)motion withEvent:(UIEvent *)event

{

}

- (void)motionEnded:(UIEventSubtype)motion withEvent:(UIEvent *)event

{

    NSLog(@"shake");

}

- (void)motionCancelled:(UIEventSubtype)motion withEvent:(UIEvent *)event

{

}

@end