2014-05-11 02:56
原题：
Write a function called FooBar that takes input integer n and prints all the numbers from upto n in a new line. If the number is divisible by then print "Foo", if the number is divisible by then print "Bar" and if the number is divisible by both and , print "FooBar". Otherwise just print the number.
for example FooBar() should print as follows: Foo Bar
Foo Foo
Bar Foo FooBar I know, easy right? ;)
题目：从1到n的整数，如果被3整除就输出Foo，如果被5整除就输出Bar，如果是公倍数就输出FooBar，否则直接输出原数。
解法：这题有什么陷阱？n可以是大数吗？n可以小于1吗？如果是实际面试，肯定要问清楚的。在此，我就按最简单的处理了。在这种题目上自找麻烦是没意义的。
代码：
// http://www.careercup.com/question?id=6543214668414976
#include <iostream>
#include <sstream>
using namespace std; int main()
{
int n;
int i; while (cin >> n && n > ) {
for (i = ; i <= n; ++i) {
if (i % ) {
if (i % ) {
cout << i;
} else {
cout << "Bar";
}
} else {
if (i % ) {
cout << "Foo";
} else {
cout << "FooBar";
}
}
cout << endl;
}
} return ;
}