1.json转model

TestModel tm = new TestModel();
JavaScriptSerializer js = new JavaScriptSerializer();
tm = js.Deserialize<TestModel>(JsonString);

2.model转json

方式1：

string Json = JsonConvert.SerializeObject(tm);

方式2：会将时间转换为 时间戳格式

JavaScriptSerializer js = new JavaScriptSerializer();

string json= js.Serialize(tm);

3.List<string> 转string

string s = string.Join(",", list.ToArray());

4.string 转 List<string>

string[] itemidList = idList.Split(',').ToArray();