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<?php// 将文本中的年份增加一年.$text = "April fools day is 04/01/2002\n";
$text.= "Last christmas was 12/24/2001\n";
// 回调函数function
next_year($matches)
{ // 通常: $matches[0]是完成的匹配
// $matches[1]是第一个捕获子组的匹配
// 以此类推
return
$matches[1].($matches[2]+1);
}echo
preg_replace_callback(
"|(\d{2}/\d{2}/)(\d{4})|",
"next_year",
$text);
?> |
输出
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April fools day is 04/01/2003Last christmas was 12/24/2002 |