问题描述
给你一个字符串s,找到s中最长的回文子串
示例1:
输入:s = "babad"
输出:"bab"
示例2:
输入:s = "cbbd"
输出:"bb"
解题思路:
https://www.bilibili.com/video/BV1SE411y7RW?from=search&seid=2950817619903450615
https://www.bilibili.com/video/BV124411X7Ly?from=search&seid=18362855079906693150
方法一:
#include<iostream>
#include <string.h>
#include<string>
using namespace std;
int main()
{
string s;
cin>>s;
if(s.size() == 0 || s.size() < 2) //一个字符也是回文字符
cout<<s;
int max = 0;
string ret = " ";
for(int i = 0;i < s.size();i++)
{
for(int j =1;j < s.size();j++)
{
string tmp = s.substr(i,j-i+1);//substr:复制子字符串,包含s中从i开始的j-i+1个字符的拷贝
string tmpr(tmp);//将字符串翻转与原字符串对比
reverse(tmp.begin(),tmp.end());//字符串进行反向排序
if(tmp == tmpr && tmpr.size() > max)
{
max = tmp.size();
ret = s.substr(i,j-i+1);
}
}
}
cout<<ret<<endl;
return 0;
}
其他方法后续更新