题目来源:144. 二叉树的前序遍历
给你二叉树的根节点 root
,返回它节点值的 前序 遍历。
示例 1:
输入:root = [1,null,2,3] 输出:[1,2,3]
示例 2:
输入:root = [] 输出:[]
示例 3:
输入:root = [1] 输出:[1]
示例 4:
输入:root = [1,2] 输出:[1,2]
示例 5:
输入:root = [1,null,2] 输出:[1,2]
/** * Definition for a binary tree node. * function TreeNode(val, left, right) { * this.val = (val===undefined ? 0 : val) * this.left = (left===undefined ? null : left) * this.right = (right===undefined ? null : right) * } */ /** * @param {TreeNode} root * @return {number[]} */ var preorderTraversal = function(root) { if(root == null){ return []; } let res = []; let cur = root; while(cur){ if(cur.left == null){ res.push(cur.val); cur = cur.right; }else{ let node = cur.left; while(node != null && node.right != null && node.right != cur){ node = node.right; } if(node.right == null){ res.push(cur.val); node.right = cur; cur = cur.left; }else{ node.right = null; cur = cur.right; } } } return res; };
提示:
- 树中节点数目在范围
[0, 100]
内 -100 <= Node.val <= 100
进阶:递归算法很简单,你可以通过迭代算法完成吗?